Question

In: Statistics and Probability

Probability

Consider randomly selecting a student at a certain university, and let A denote the event that the selected individual has a Visa credit card and B be the analogous event for a MasterCard. Suppose that P(A)=0.5 , P(B)=0.4 and P(A\( \cap \)B)=0.25.

(a) Compute the probability that the selected individual has at least one of the two types of cards (i.e., the probability of the event A\( \cup \)B).

(b) What is the probability that the selected individual has neither type of card?

(c) Describe, in terms of A and B, the event that the selected student has a Visa card but not a MasterCard, and then calculate the probability of this event.

Solutions

Expert Solution

solution 

A : individual has a visa card 

B : individual has a master card 

(a) Compute the probability that the selected individual has at least one of the two types of cards (i.e., the probability of the event A\( \cup \)B)

P(A\( \cup \)B)=P(A)+P(B)-P(A\( \cap \)B)

           =0.5+0.4-0.25=0.65

(b) What is the probability that the selected individual has neither type of card?

P(\( \overline{A\cup B} \))=1-P(A\( \cup \)B)=1-0.65=0.35

(c) Describe, in terms of A and B, the event that the selected student has a Visa card but not a MasterCard, and then calculate the probability of this event.

P(A\( \cap \bar B \))=P(A)-P(A\( \cap \)B)=0.5-0.25=0.25


Answer

(a) . P(A\( \cap \)B)=0.65

(b). P(\( \overline{A\cup B} \))=0.35

(c). P(A \( \cap \bar B \) )=0.25

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