A thin piece of glue of index of refraction n=1.33is formed in the shape of a...

A thin piece of glue of index of refraction n=1.33is formed in the shape of a wedge. The wedge is 9μmat its thickest point.light of wavelength 610 nm is shone from above. The wedge is 8cm long

(a) When viewed in transmission ,what is the distance between the corner and the m=7 maximum?

(b) What is the distance between two consecutive bright fringes viewed in reflection?

(d) How many full bright fringes do you see if the wedge were to float on a liquid of n=1.4

(e) How much larger is the distance between two dark fringes viewed in reflection as opposed to that obtained when viewed in transmission?

Solutions

Expert Solution

Given data,

refractive index n=1.33

thickest point of the wedge has height dmax=9 *10-6 m

wedge has a length 8 cm.

Wavlength of light is .

(a),(b),(c),(d) have been explained with diagram and solved in attached hand written notes. Please follow.

genius_generous answered 1 year ago

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