Phosphorus-32 decays by beta emission to form sulfur-32. How many half-lives have passed in the...

Part A

Phosphorus-32 decays by beta emission to form sulfur-32. How many half-lives have passed in the reaction shown here?

Part B

The half-life of phosphorus-32 is 14.26 days. Calculate its decay constant.

Radioactive decay is characterized by the equation where No is the initial amount, N is the amount remaining at time, and k is the rate constant. The half-life ()is the time required for the number of radioactive nuclei in a sample to drop to half of its initial value. It is defined as T 1/2=ln2/k

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Expert Solution

queen_honey_blossom answered 2 years ago

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