In: Physics
Derive equation of a rocket with the rocket accelerating in a large stationary control volume using integral momentum equation and also the rocket mass is changing with time
A large fraction (typically 90%) of the mass of a rocket is propellant, thus it is important to consider the change in mass of the vehicle as it accelerates.
There are several ways to do this through applying conservation
of momentum. Here we will apply the momentum theorem differentially
by considering a small mass, , expelled from the rocket
during time
, Figure 14.2.
The initial momentum of the mass in the control volume (the
vehicle) is . The final momentum of mass in
the control volume (the vehicle and the mass expelled,
) is
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The change in momentum during the interval is
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|
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since is a higher order term. Now
consider the forces acting on the system which is composed of the
masses
(the rocket), and
(the small amount of propellant
expelled from the rocket during time
):
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Applying conservation of momentum, the resulting impulse,
, must balance the change in
momentum of the system:
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Then since
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where is the propellant mass flow
rate, we have
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(14..1) |
Equation 14.1 is known as The Rocket Equation. It can be integrated as a function of time to determine the velocity of the rocket.
If we set , assume that at
,
, neglect drag, and set
, then we can simplify the
rocket equation to
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which can be integrated to give
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where is the initial mass of the
rocket. We can also write this result as
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We can view this equation as being similar to the Breguet Range
Equation for aircraft. It presents the overall dependence of the
principal performance parameter for a rocket (velocity, ), on the efficiency of the
propulsion system (Isp), and the structural design (ratio of total
mass to structural mass, since the initial mass is the fuel mass
plus the structural mass and the final mass is only the structural
mass).
Assuming the rate of fuel consumption is constant, the mass of the rocket varies over time as
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where is the time at which all of the
propellant is used. This expression can be substituted into the
equation for velocity and then integrated to find the height at the
end of burnout:
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which for a single stage sounding rocket with no drag and constant gravity yields
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The final height of the rocket can then be determined by equating the kinetic energy of the vehicle at burnout with its change in potential energy between that point and the maximum height.