Make a 95% confidence interval for sigma squared if: s²=83.72 n=36

Make a 95% confidence interval for sigma squared if:
s²=83.72
n=36

Expert Solution

Solution :

Given that,

s² = 83.72

Degrees of freedom = df = n - 1 = 35

²_L = ²_/2,df = 53.203

²_R = ²_{1 -} _/2,df = 20.569

The 95% confidence interval for is,

(n - 1)s² / ²_/2 < < (n - 1)s² / ²_{1 -} _/2

35 * 83.72 / 53.203 < < 35 * 83.72 / 20.569

7.42 < < 11.54

(7.42 , 11.54)

orchestra answered 2 years ago

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