Question

In: Statistics and Probability

Make a 95% confidence interval for sigma squared if: s²=83.72 n=36

Make a 95% confidence interval for sigma squared if:
s²=83.72
n=36

Solutions

Expert Solution

Solution :

Given that,

s2 = 83.72

Degrees of freedom = df = n - 1 = 35

2L = 2/2,df = 53.203

2R = 21 - /2,df = 20.569

The 95% confidence interval for is,

(n - 1)s2 / 2/2 < < (n - 1)s2 / 21 - /2

  35 * 83.72 / 53.203 < < 35 * 83.72 / 20.569

7.42 < < 11.54

(7.42 , 11.54)


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