In: Physics
For a
small body orbiting another much larger body, such as a satellite
orbiting Earth, the total energy of the smaller body is the sum of
its kinetic energy and potential energy, and this total energy also
equals half the potential at the average distance
(the semi-major axis):
Solving this equation for velocity results in the vis-viva equation,
where:
Therefore, the delta-v (Δv) required for the Hohmann transfer can be computed as follows, under the assumption of instantaneous impulses:
to enter the elliptical orbit at
from the
circular orbit
to leave the elliptical orbit at
to the
circular orbit, where
and r 2
are respectively the radii of the departure and arrival circular
orbits; the smaller (greater) of
and
corresponds to the periapsis distance (apoapsis distance) of the
Hohmann elliptical transfer orbit. Typically,
is given in units of m3/s2, as such be sure to use meters, not
kilometers, for
and
. The total
is then:
Whether moving into a higher or lower orbit, by Kepler's third law, the time taken to transfer between the orbits is
(one
half of the orbital period for the whole ellipse), where
is length of semi-major axis of the Hohmann transfer orbit.
In application to traveling from one celestial body to another it is crucial to start maneuver at the time when the two bodies are properly aligned. Considering the target angular velocity being
angular alignment α (in radians) at the time of start between the source object and the target object shall be