In: Statistics and Probability
The following information is taken from the 2019 Traffic Safety Report for Jefferson county. It looks at all collisions with animals and splits them up into two categories: collisions with domestic animals and collisions with wild animals.
Year | Domestic Animal | Wild Animal | Total |
2015 | 4 | 28 | 32 |
2016 | 6 | 29 | 35 |
Total | 10 | 58 | 67 |
Your friend says they got in a crash with an animal and they are
about to tell you a story. Match each phrase to it's probability
notation:
a. The probability of the animal being wild, given that it is
2015. --- wild|2015 P(wild|2015) P(wild) 2015
P(2015|wild)
b. The probability that the collision was in 2015. ---
P(wild) P(2015) P(2015|collision) 2015 wild|2015
Find the following probabilities. Enter your answers with at least
2 decimal places
c. P(Domestic|2016) =
d. P(Wild)=
Explanation:-
Given data
year | Domestic animal | wild animal | total |
2015 | 4 | 28 | 32 |
2016 | 6 | 29 | 35 |
total | 10 | 57 | 67 |
a) The relative frequencies of above table
year | Domestic animal | wild animal | total |
2015 | 0.48 | ||
2016 | 0.52 | ||
total | 0.15 | 0.85 | 1 |
The sum of conditional probabilities is equal to one
P(2015) = P(domestic or 2015) +P(wild or 2015) = 0.06+0.42 =0.48
P(2016) = P(domestic or 2016) +P(wild or 2016) = 0.09+0.43 =0.52
c)
year | Domestic animal | wild animal | total |
2015 | 0.48 | ||
2016 | 0.52 | ||
total | 0.15 | 0.85 | 1 |
a)
b)
year | Domestic animal | wild animal | total |
2015 | 0.48 | ||
2016 | 0.52 | ||
total | 0.15 | 0.85 | 1 |
c)
The probability of domestic animal
= P( domestic and 2015) or P(domestic and 2016)
= 0.06 + 0.09 =0.15
The probability of wild animal
= P( wild and 2015) or P(wild and 2016)
= 0.42 + 0.43 =0.85