prove that the square of the product of 3 consecutive integers is always divisible by 12

Expert Solution

if n(n+1)(n+2) is divisible by 6

than (n(n+1)(n+2))² = (6l)² = 36??l² is divisible by 12

hence square of the product of 3 consecutive integers is always divisible by 12?

Colby Messinger answered 3 years ago

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