In: Statistics and Probability
The following table is obtained:
Categories | Observed | Expected | (fo-fe)2/fe |
Category 1 | 68 | 200*0.37=74 | (68-74)2/74 = 0.486 |
Category 2 | 51 | 200*0.23=46 | (51-46)2/46 = 0.543 |
Category 3 | 42 | 200*0.17=34 | (42-34)2/34 = 1.882 |
Category 4 | 8 | 200*0.05=10 | (8-10)2/10 = 0.4 |
Category 5 | 31 | 200*0.18=36 | (31-36)2/36 = 0.694 |
Sum = | 200 | 200 | 4.007 |
5) Conclusion
It is concluded that the null hypothesis Ho is not rejected. Therefore, there is NOT enough evidence to claim that
the percentage differ from those stated the chart at the α=0.05 significance level