Question

What effect does increasing the mass of gas in a fixed container have on oomph/collision? Assume that volume and temperature of the container remains constant.

	A.	Increase
	B.	Decrease
	C.	Remain the same

Which particles have kinetic energy?

	A.	Solid particles
	B.	Liquid particles
	C.	Gas particles
	D.	Solid and liquid particles
	E.	Solid, liquid, and gas particles

The space between which particles will increase as the substance is heated?

	A.	Solid particles
	B.	Liquid particles
	C.	Gas particles
	D.	Solid and liquid particles
	E.	Solid, liquid, and gas particles

What effect does decreasing the volume of the container have on #collision/second? Assume that the temperature and the mass of gas in the container remains constant.

	A.	Increase
	B.	Decrease
	C.	Remain the same

What effect does increasing the mass of gas in a fixed container have on pressure of gas? Assume that volume and temperature of the container remains constant.

	A.	Increase
	B.	Decrease
	C.	Remain the same

What effect does increasing the temperature of gas in a fixed container have on oomph/collision? Assume that the volume and the mass of gas in the container remains constant.

	A.	Increase
	B.	Decrease
	C.	Remain the same

Answer 1

Answers ;-

(1) option A is correct

From ideal gas equation , PV = nRT , As V and T are constant so , P is directly proportional to n , where n is the number of moles which is equal to ( m / M ) , m is the mass of the gas and M is the molecular weight of the gas , So as m increases P increases which indicates number of collision increases .

(2) option E is correct , The reason is that solid particles  have a very low kinetic energy so  they carry that small amount and the liquid particles also having kinetic energy but smaller than gas particles and greater than the solids particles , while gas particles has very high kinetic energy among all .

(3) option B is correct , As the substance is heated the space between the liquid particles is increases and it changes to gas phase as the heating is continuous .

(4) As temperature ( T ) and mass of gas in the container ( m) is constant , from gas equation PV=nRT

PV=(m/M)*RT

PV= Constant

As the value of V is decreases then P increases which means number of collision increases .

option ( A) is correct

(5) same as (1) question

(6) from gas equation PV=(m/M)*RT

As V and m are constant , so P is directly proportional to the temperature so as the temperature is increases then corresponding pressure is also increasing which means number of collision increases .

option (A) is correct