Question

In: Statistics and Probability

The service life X of a car tire has a Normal probability distribution with µ =...

The service life X of a car tire has a Normal probability distribution with µ = 50,000 miles and σ = 5500 miles. What is the probability that the useful life of a tire is greater than 3500 miles but less than 60,000 miles?

Solutions

Expert Solution

Here in this Question it is given that the life of x car tires has mean 50000 and Standerd deviation is 5500.

Then we have to calculate the probability that the useful life of a car tires has life time in between 3500 and 60000 miles.

Here to calculate the above probability we have to use normal distribution method,

The standard z value is Z1​= X1−μ/σ.

Using this method we calculated the probability as below,

Note that the probability value is calculated using the standard normal z-table or using Statistical software like excel.

The probability that the useful life of a tire is greater than 3500 mile but less than 60,000 mile is 0.9655.

The above shaded area represents the probability that the car tires has life time between 3500 miles and 60000 mile.

Hope it helps.

Thank you.


Related Solutions

Let X be a continuous random variable having a normal probability distribution with mean µ =...
Let X be a continuous random variable having a normal probability distribution with mean µ = 210 and standard deviation σ = 15. (a) Draw a sketch of the density function of X. (b) Find a value x∗ which cuts left tail of area 0.25 . (c) Find a value y∗ which cuts right tail of area 0.30. (d) Find a and b such that p(a ≤ X ≤ b) = 0.78.
The notation X ~ N (µ, σ) means that the RV X has a normal distribution...
The notation X ~ N (µ, σ) means that the RV X has a normal distribution with mean µ and standard deviation σ. USE A RULER FOR ALL DRAWINGS. 1. What is the z-score of x, when x = 1, and X ~ N (12, 3)? 2. The average score on a math test was 70 points with a standard deviation of 12 points. Jane’s z-score was 2.2. How many points did she score? 3. In 2009, Guinness World Records...
Given a normal distribution with µ = 47 and σ = 6, what is the probability...
Given a normal distribution with µ = 47 and σ = 6, what is the probability that: X < 39 or X > 44 X is between 37 and 46 7% of the values are less than what X value. Between what two X values (symmetrically distributed around the mean) are 70% of the values?
A tire manufacturer believes that the life of its tires follow a normal distribution with a...
A tire manufacturer believes that the life of its tires follow a normal distribution with a mean of 46,000 miles and a standard deviation of 4,000 miles. What mileage can he guarantee each tire to last so that 99% of the tires last longer than the guaranteed lifetime?
The tread life (x)  of tires follow  normal distribution with µ =  60,000 and σ= 6000 miles.  The manufacturer guarantees...
The tread life (x)  of tires follow  normal distribution with µ =  60,000 and σ= 6000 miles.  The manufacturer guarantees the tread life for the first 52,000 miles. (i) What proportion of tires last  at least 55,000 miles? (ii)  What proportion of the tires will need to be replaced under warranty? (iii)  If you buy 36 tires,  what is the probability that the  average life of your 36 tires will exceed  61,000?  (iv) The manufacturer is willing to replace only 3% of its tires under a warranty program involving tread life.  Find...
Suppose X has a Normal distribution with mean µ= 50 and standard deviation σ = 8....
Suppose X has a Normal distribution with mean µ= 50 and standard deviation σ = 8. What percent of X is between 42 and 58? What percent of X is greater than 66? What is the value of X for which 10% of the distribution is less? Determine the 35th percentile.
Question 1 Given a normal distribution with µ=15 and σ = 5, what is the probability...
Question 1 Given a normal distribution with µ=15 and σ = 5, what is the probability that X>20 X<20 X<20 or X>20 INSTRUCTIONS: Show all your work as to how you have reached your answer. Please don’t simply state the results. Show graphs where necessary.
Assume that X has a normal distribution, and find the indicated probability. The mean is  = 85.0...
Assume that X has a normal distribution, and find the indicated probability. The mean is  = 85.0 and the standard deviation is s = 12.0.  Find the probability that X is greater than 101.8. 0.0808                          b.   0.9192                    c.   0.7881                     d.   0.2119 The mean is  = 42 and the standard deviation is s = 6.  Find the probability that X is less than 51. 0.0668                          b.   0.9901                    c.    0.9332                    d.   0.0099 The mean is  = 120 and the standard deviation is s = 13.2.  Find P(138  140). 0.8488                          b.   0.0226                    c.   0.1512                     d.   0.9774 Find the indicated Probability. A bank’s loan office uses credit scores in...
In an examination the probability distribution of scores (X) can be approximated by normal distribution with...
In an examination the probability distribution of scores (X) can be approximated by normal distribution with mean 64.9 and standard deviation 9.4. Suppose one has to obtain at least 55 to pass the exam. What is the probability that a randomly selected student passed the exam? [Answer to 3 decimal places] Tries 0/5 If two students are selected randomly what is the chance that both the students failed? [Answer to 3 decimal places] Tries 0/5 If only top 4% students...
It is known that the thread life of a certain type of tire has a normal...
It is known that the thread life of a certain type of tire has a normal distribution with standard deviation of 1500. a) A sample of 16 tires is found to have an average thread life of 30960. Does this provide sufficient evidence at 1% level of significance to conclude that the true average thread life of this type of tires is more than 30000? Explain by carrying out an appropriate hypothesis test stating clearly the hypotheses. b) What is...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT