Question

In: Statistics and Probability

Wendy wants to estimate the mean number of hours that college students sleep each night. She...

Wendy wants to estimate the mean number of hours that college students sleep each night. She obtains a simple random sample of 41 college students and finds that the sample mean is 6.7 with a standard deviation of 1.9. Construct a 90% confidence interval to estimate the population mean and interpret your answer in a complete sentence (round numbers to 1 decimal place).

Solutions

Expert Solution


Solution :

Given that,

= 6.7

s = 1.9

n = 41

Degrees of freedom = df = n - 1 = 41 - 1 = 40

At 90% confidence level the z is ,

= 1 - 90% = 1 - 0.90 = 0.10

/ 2 = 0.10 / 2 = 0.05

t /2,df = t0.05,40 =1.684

Margin of error = E = t/2,df * (s /n)

= 1.684 * ( 1.9 / 41)

= 0.5

Margin of error = 0.5

The 90% confidence interval estimate of the population mean is,

- E < < + E

6.7 - 0.5 < < 6.7 + 0.5

6.2 < < 7.2

(6.2, 7.2 )


Related Solutions

Wendy wants to estimate the mean number of hours that college students sleep each night. She...
Wendy wants to estimate the mean number of hours that college students sleep each night. She obtains a simple random sample of 41 college students and finds that the sample mean is 6.7 with a standard deviation of 1.9. Construct a 90% confidence interval to estimate the population mean and interpret your answer in a complete sentence (round numbers to 1 decimal place).
A professor thinks that the mean number of hours that students study the night before a...
A professor thinks that the mean number of hours that students study the night before a test is 1.75. He selected a random sample of 12 students and found that the mean number of study hours was 2.44 and the standard deviation is 1.26 hours. Test the professor’s claim at α = 0.01. a 1-6) Give the hypotheses for H0 (a1, a2 and a3) and H1 (a4, a5 and a6) H0 a1) µ or p a2) =, ≥, ≤ a3)...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 50 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.2 hours with a standard deviation of 0.86hours. We want to construct a 95% confidence interval for the mean nightly hours of sleep...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is 7.0 hours with a standard deviation of 1.3 hours. You randomly select 50 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.40 hours. Assume the population standard deviation for college students is the same as for all people....
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 45 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.2 hours with a standard deviation of 0.97 hours. We want to construct a 95% confidence interval for the mean nightly hours of...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college...
Sleep – College Students: Suppose you perform a study about the hours of sleep that college students get. You know that for all people, the average is about 7 hours. You randomly select 35 college students and survey them on their sleep habits. From this sample, the mean number of hours of sleep is found to be 6.1 hours with a standard deviation of 0.97 hours. You want to construct a 99% confidence interval for the mean nightly hours of...
In a class survey, students are asked how many hours they sleep per night. In the...
In a class survey, students are asked how many hours they sleep per night. In the random sample of 18 students, the (sample) mean is 6.8 hours with a (sample) standard deviation of 1.9 hours. We wish to know if this shows that the class’s student population on average has not gotten at least the recommended 8 hours of sleep at the α = .1 level. The distribution of sleep for this population follows a normal distribution. c) Please use...
Question 1: A researcher would like to estimate the true mean number of hours adults sleep...
Question 1: A researcher would like to estimate the true mean number of hours adults sleep at night. Suppose that population sleep time is known to follow a Normal distribution with standard deviation as 1.5 hours. The researcher random select 100 people and found the average sleeping hours for the sample of 100 people is 6.5 hours. 1) Use this sample mean to estimate the true population mean of sleep time with 95% confidence. (hint: 95% CI) 2) If the...
Average Sleep Time on a School Night Students 4 hours 8 5 hours 9 6 hours...
Average Sleep Time on a School Night Students 4 hours 8 5 hours 9 6 hours 14 7 hours 12 8 hours 15 9 hours 4 10 hours 0 Ho: 72.7% of high school students (grade 9-12) do not get enough sleep at night. (minimum 8 hours) (article claim) Ha: 72.7% of high school students (grade 9-12) do get enough sleep at night. Record the hypothesis test. Use 5% level of significance Include 95% confidence interval on solution sheet. Create...
Average Sleep Time on a School Night Students 4 hours 8 5 hours 9 6 hours...
Average Sleep Time on a School Night Students 4 hours 8 5 hours 9 6 hours 14 7 hours 12 8 hours 15 9 hours 4 10 hours 0 Ho: 72.7% of high school students (grade 9-12) do not get enough sleep at night. (minimum 8 hours) Ha: 72.7% of high school students (grade 9-12) do get enough sleep at night. Sample size: Sample mean: Sample deviation: Record the hypothesis test. Use 5% level of significance Include 95% confidence interval...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT