A 1200-kg car moving at 25 m/s suddenly collides with a stationary car of mass 1,002 If the...

A 1200-kg car moving at 25 m/s suddenly collides with a stationary car of mass 1,002 If the two vehicles lock together, what energy was lost to heat?

Solutions

Expert Solution

By conservation of momentum, momentum before collision=momentum after collision

+=(+)V

=1200kg

=1002kg

=velocity of before collision=25m/s

=velocity of before collision=0

V=combined velocity after collision( as they locked)

+=(+)V

V=[+]/(+)=[(1200x25)+0]/(1200+1002)=1200x25/2202

V=13.62m/s

Kinetic energy before collision=()/2+0=(1200x)/2=375000joule

Kinetic energy after collision=[(+)]/2=[(1200+1002)x]/2=204240joule

Energy lost to heat=375000-204240=170760joule=1.708xjoule

genius_generous answered 1 year ago

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