Question

In: Statistics and Probability

The dean of a university estimates that the mean number of classroom hours per week for​...

The dean of a university estimates that the mean number of classroom hours per week for​ full-time faculty is 11.0. As a member of the student​ council, you want to test this claim. A random sample of the number of classroom hours for eight​ full-time faculty for one week is shown in the table below. At alphaequals0.05​, can you reject the​ dean's claim? Complete parts​ (a) through​ (d) below. Assume the population is normally distributed. 11.2 9.8 13.2 8.1 5.4 9.5 14.5 9.6 ​

(a) Write the claim mathematically and identify Upper H 0 and Upper H Subscript a.

Which of the following correctly states Upper H 0 and Upper H Subscript a​? A.

Upper H 0​: muequals11.0 Upper H Subscript a​: munot equals11.0

B. Upper H 0​: muless than or equals11.0 Upper H Subscript a​: mugreater than11.0

C. Upper H 0​: mugreater than or equals11.0 Upper H Subscript a​: muless than11.0

D. Upper H 0​: mugreater than11.0 Upper H Subscript a​: muless than or equals11.0

E. Upper H 0​: munot equals11.0 Upper H Subscript a​: muequals11.0

F. Upper H 0​: muless than11.0 Upper H Subscript a​: mugreater than or equals11.0 ​

(b) Use technology to find the​ P-value.

Pequals =  ​(Round to three decimal places as​ needed.) ​

(c) Decide whether to reject or fail to reject the null hypothesis.

Which of the following is​ correct?

A. Fail to reject Upper H 0 because the​ P-value is less than the significance level.

B. Reject Upper H 0 because the​ P-value is greater than the significance level.

C. Reject Upper H 0 because the​ P-value is less than the significance level.

D. Fail to reject Upper H 0 because the​ P-value is greater than the significance level.

​(d) Interpret the decision in the context of the original claim.

A. At the 5​% level of​ significance, there is sufficient evidence to reject the claim that the mean number of classroom hours per week for​ full-time faculty is greater than 11.0.

B. At the 5​% level of​ significance, there is sufficient evidence to reject the claim that the mean number of classroom hours per week for​ full-time faculty is 11.0.

C. At the 5​% level of​ significance, there is not sufficient evidence to reject the claim that the mean number of classroom hours per week for​ full-time faculty is less than 11.0.

D. At the 5​% level of​ significance, there is not sufficient evidence to reject the claim that the mean number of classroom hours per week for​ full-time faculty is 11.0. Click to select your answer(s).

Solutions

Expert Solution

a. Here claim is that mean is 11

So hypothesis is

A. vs

b. Sample mean is

Create the following table.

data data-mean (data - mean)2
11.2 1.0375 1.07640625
9.8 -0.3625 0.13140625
13.2 3.0375 9.22640625
8.1 -2.0625 4.25390625
5.4 -4.7625 22.68140625
9.5 -0.6625 0.43890625
14.5 4.3375 18.81390625
9.6 -0.5625 0.31640625

Find the sum of numbers in the last column to get.

So standard deviation is

So test statistics is

Hence P value is TDIST(0.83,7,2)=0.4339

c. As P value is greater than alpha=0.05, we fail to reject the null hypothesis

Correct answer is

D. Fail to reject Upper H 0 because the​ P-value is greater than the significance level.

d. Hence we have sufficient evidence to support the claim that mean is 11

So answer here is D. At the 5​% level of​ significance, there is not sufficient evidence to reject the claim that the mean number of classroom hours per week for​ full-time faculty is 11.0.


Related Solutions

The dean of a University estimates that the mean number of classroom hours for full time...
The dean of a University estimates that the mean number of classroom hours for full time faculty is 11.0. As a member of sydent council, you want to test the claim. A sample of the number of classroom hours for 8 full-time faculty is shown below.                  11.8 6.4 8.6 10.4 12.6 13.6 7.9 9.1 At the .01 level of significance, is the Dean’s claim valid? Use the P-value approach. Clearly state the null and alternative hypotheses. Locate the claim and...
a consultant for a large university studied the number of hours per week freshmen watch tv...
a consultant for a large university studied the number of hours per week freshmen watch tv versus the number of hours seniors do. the results of this study follow. is there enough evidence to show the mean number of hours per week freshmen watch tv is different from the mean number of hours seniors do at alpha=.1. freshmen n=10, xbar=18.6, s=7.8740 seniors n=4, xbar=11.4, s=3.9749
a consultant for a large university studied the number of hours per week freshmen watch tv...
a consultant for a large university studied the number of hours per week freshmen watch tv versus the number of hours seniors do. the results of this study follow. is there enough evidence to show the mean number of hours per week freshmen watch tv is different from the mean number of hours seniors do at alpha=.1. freshmen n=10, xbar=18.6, s=7.8740 seniors n=4, xbar=11.4, s=3.9749
A consultant for a large university studied the number of hours per week freshmen watch TV...
A consultant for a large university studied the number of hours per week freshmen watch TV versus the number of hours seniors do. The result of this study follow. Is there enough evidence to show the mean number of hours per week freshman watch TV is different from the mean number of hours seniors do at alpha= 0.01? Freshmen Seniors n 8 4 xbar 18.2 11.9 s 7.8740 3.9749 For the Hypothesis stated above (in terms of Seniors- Freshmen) What...
, believes that the mean number of hours per day all male students at the University...
, believes that the mean number of hours per day all male students at the University use cell/mobile phones exceeds the mean number of hours per day all female students at the University use cell/mobile phones. To test President Loh’s belief, you analyze data from 29 male students enrolled in BMGT 230/230B this semester and 13 female students enrolled in BMGT 230/230B this semester. a. Assuming equal population variances, if the level of significance equals 0.05 and the one-tail p-VALUE...
The belief is that the mean number of hours per week of part-time work of high...
The belief is that the mean number of hours per week of part-time work of high school seniors in a city is 10.4 hours. Data from a simple random sample of 28 high school seniors indicated that their mean number of part-time work was 11.5 with a standard deviation of 1.3. Test whether these data cast doubt on the current belief. (use α = 0.05) 1.) State your null and alternative hypotheses. 2.) State the rejection region. 3.) Calculate the...
The belief is that the mean number of hours per week of part-time work of high...
The belief is that the mean number of hours per week of part-time work of high school seniors in a city is 10.4 hours. Data from a simple random sample of 21 high school seniors indicated that their mean number of part-time work was 11.4 with a standard deviation of 1.2. Test whether these data cast doubt on the current belief. (use α = 0.05) Part a: State your null and alternative hypotheses. Part b: State the rejection region. Part...
The student union wants to determine the mean number of hours per week a student at...
The student union wants to determine the mean number of hours per week a student at Okanagan College studies. To accomplish this, they passed a questionnaire to 14 randomly chosen students among first and second year status. They also wanted insure an equal number of men and women to possibly investigate gender differences. The results were: Year of study 1 2 1 1 2 2 1 1 2 2 2 1 1 2 Mean hours studied per week 4 12...
In a recent study of 53 ninth-grade students, the mean number of hours per week that...
In a recent study of 53 ninth-grade students, the mean number of hours per week that they played video games was 72. The standard deviation of the population was 4.3. Find the 84% confidence interval for the mean of the time playing video games.
The number of hours spent per week on household chores by all adults has a mean...
The number of hours spent per week on household chores by all adults has a mean of 28.6 hours and a standard deviation of 8.8 hours. The probability, rounded to four decimal places, that the mean number of hours spent per week on household chores by a sample of 64 adults will be more than 26.75 is:
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT