In: Statistics and Probability
The number of hours spent per week on household chores by all adults has a mean of 28.6 hours and a standard deviation of 8.8 hours. The probability, rounded to four decimal places, that the mean number of hours spent per week on household chores by a sample of 64 adults will be more than 26.75 is:
Solution :
Given that,
mean =
= 28.6
standard deviation =
= 8.8
n=64
=
=28.6
=
/
n = 8.8/
64 = 1.1
P( > 26.75) = 1 - P(
<26.75 )
= 1 - P[(
-
) /
< (26.75-28.6) /1.1 ]
= 1 - P(z < -1.68)
Using z table
= 1 - 0.0465
= 0.9535
probability= 0.9535