Question

In: Physics

Torque can be calculated by multiplying the force (N) applied at 90° to the lever arm at a distance (m) from the pivot point (point of rotation)

Torque can be calculated by multiplying the force (N) applied at 90° to the lever arm at a distance (m) from the pivot point (point of rotation), the compound SI unit for the torque is N⋅m. If the force (at 90° to the lever arm) applied is 15 N and it is applied at 2.0 m from the pivot point (point of rotation), what is the torque on the lever?

Solutions

Expert Solution

\,

The magnitude of torque is given by the equation,

\,

\tau =Fd \sin \theta

\,

inserting the data given,

\,

\tau =(15N)(2m)( \sin 90^{\circ} )

\,

or

\,

{\color{Blue} \tau =30 \, N \cdot m}

genius_generous answered 2 years ago
Next > < Previous

Related Solutions

An object that weighs 1180 N rests on a lever at a point 0.370 m from...
An object that weighs 1180 N rests on a lever at a point 0.370 m from a support. On the same side of the support, at a distance of 3.00 m from it, an upward force with magnitude F is applied. Ignore the weight of the board itself. If the system is in equilibrium, what is F? Express your answer in Newtons. where P = 1180 and x = 0.370. N
A pitcher rotates his arm to throw a baseball. The distance from the centre of rotation...
A pitcher rotates his arm to throw a baseball. The distance from the centre of rotation of the pitcher's arm to his hand is 110 cm and remains constant over the throw. At the start of the throw, the pitcher's arm is already rotating at 0.250 rad/s and it takes him 250 ms to complete the throw. if the arc length that his hand traces over the throw is 2.70m, calculate the transverse velocity of his hand at the end...
A 27 N-m torque is applied to a flywheel that rotates about a fixed axis. The...
A 27 N-m torque is applied to a flywheel that rotates about a fixed axis. The flywheel has a moment of inertia of 33 kg/m2. If the flywheel is initially at rest, what is its angular velocity in rad/s after it has turned through 5 revolutions?
A torque of 36.2 N · m is applied to an initially motionless wheel which rotates...
A torque of 36.2 N · m is applied to an initially motionless wheel which rotates around a fixed axis. This torque is the result of a directed force combined with a friction force. As a result of the applied torque the angular speed of the wheel increases from 0 to 10.1 rad/s. After 6.20 s the directed force is removed, and the wheel comes to rest 59.4 s later. From the time the directed force is initially applied, how...
A torque of 36.2 N · m is applied to an initially motionless wheel which rotates...
A torque of 36.2 N · m is applied to an initially motionless wheel which rotates around a fixed axis. This torque is the result of a directed force combined with a friction force. As a result of the applied torque the angular speed of the wheel increases from 0 to 9.5 rad/s. After 6.10 s the directed force is removed, and the wheel comes to rest 60.2 s later. A- What is the wheel's moment of inertia B- What...
A net torque of 2.84 N*m is applied on a solid sphere for 5.32 seconds. If...
A net torque of 2.84 N*m is applied on a solid sphere for 5.32 seconds. If the solid sphere has a moment of inertia of 2.96 kg*m^2 and it starts from rest, what is its final rotational kinetic energy?
​A force of magnitude 50 N is applied at the bottom point of a disk of radius 5 m that is pinned at P (leftmost point) as shown in the figure.
8.A force of magnitude 50 N is applied at the bottom point of a disk of radius 5 m that is pinned at P (leftmost point) as shown in the figure.(a) Find the angle between the force and the vector from P to Q. (b) Find the magnitude of the applied torque. 9.A torque wrench grips a bolt at the origin of coordinates, with the free end of the torque wrench located at the point (r0, 0, 0). The force on this...
why the longer the distance a force is applied from the fulcrum the greater the output...
why the longer the distance a force is applied from the fulcrum the greater the output force. I want to know how this works exactly and how does a larger distance affects the amount if work done by the force. does it has to do with the input force traveling longer vertically some how creating a greater output? So far I've just gotten very general information I hope you can help me to understand this more deeply thank you.
A force of 250 N is applied to a hydraulic jack piston that is 0.02 m...
A force of 250 N is applied to a hydraulic jack piston that is 0.02 m in diameter. If the piston that supports the load has a diameter of 0.15 m, approximately how much mass can be lifted by the jack? Ignore any difference in height between the pistons.   A) 250 kg B) 700 kg C) 1400 kg D) 2800 kg E) 5600 kg
QUESTION 1: Two point masses are the same distance R from an axis of rotation and...
QUESTION 1: Two point masses are the same distance R from an axis of rotation and have moments of inertia IA and IB. (a) If IB = 4IA, what is the ratio mB mA of the two masses? mB mA = (b) In terms of R, at what distance from the axis of rotation should mass A be placed so that IA = IB? R QUESTION 2: A large grinding wheel in the shape of a solid cylinder of radius...
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT