In: Economics
Alternatives A and B are being evaluated. The effective annual interest rate is 10%. What
alternative is economically superior?
Alternative A | Alternative B | |
first cost | 80,000 | 35,000 |
life | 20 years | 10 years |
salvage value | 7,000 | 0 |
annual costs | ||
years 1-5 | 1000 | 3000 |
years 6-10 | 1500 | 4000 |
years 11 - 20 | 2000 | 0 |
additional cost | ||
year 10 | 5000 | 0 |
We need to find Equivalent annual worth
Annual cost cash flow for A will be 1000 for yr 1 to 20 and extra 500 from yr 6 to 20 and extra 500 from yr 11 to 20
Annual cost cash flow for B will be 3000 from yr 1 to 10 and extra 1000 from yr 6 to 10
Present value of cash flow starting from other than year 1 will be calculated and then changed to annual series
Equivalent annual worth of option A
= -80000 *(A/P, 10%, 20) + 7000* (A/F, 10%,20)-1000-500 *(P/A, 10%, 15)*(P/F, 10%, 5) *(A/P, 10%, 20) -500 * (P/A, 10%, 10)*(P/F, 10%, 10) *(A/P, 10%, 20) - 5000 *(P/F, 10%, 10) *(A/P, 10%, 20)
= -80000 *0.1174596 + 7000*0.0174596 - 1000 - 500 *7.606079*0.620921323 *0.1174596 -500 *6.144567*0.3855432 *0.1174596 - 5000 *0.3855432 *0.1174596
= -10917.48
Equivalent annual of option B
= -35000 *(A/P, 10%, 10) -3000 -1000*(P/A, 10%, 5)*(P/F, 10%, 5) *(A/P, 10%, 10)
= -35000 *0.16274539 -3000 -1000*3.790786*0.620921323 *0.16274539
= -9079.155
Alternative B is economically superior as it has less annual cost