In: Chemistry
Consider the following reaction
A(aq) <=> 2B(aq) Kc= 9.07x10^-6 at 500K
If a 4.90 M sample of A is heated to 500 K, what is the concentration of B at equilibrium?
For the given reaction -
Kc = [B]2 / [A]
For the equilibrium -
A (aq) <--------> 2 B (aq)
I(M) 4.90 0
C -x +2x
Eq (4.90-x) 2x
Hence -
Kc = 9.07*10-6 = (2x)2 / (4.90-x)
By solving - x = 0.0033 M
Therefore [B] at equilibrium = 2(0.0033) = 0.0066 M