Question

In: Chemistry

Consider the following reaction A(aq) <=> 2B(aq) Kc= 9.07x10^-6 at 500K If a 4.90 M sample...

Consider the following reaction

A(aq) <=> 2B(aq) Kc= 9.07x10^-6 at 500K

If a 4.90 M sample of A is heated to 500 K, what is the concentration of B at equilibrium?

Solutions

Expert Solution

For the given reaction -

              Kc = [B]2 / [A]

For the equilibrium -

              A (aq) <--------> 2 B (aq)

I(M)      4.90                   0

C          -x                     +2x

Eq       (4.90-x)               2x

Hence -

               Kc = 9.07*10-6 = (2x)2 / (4.90-x)

By solving - x = 0.0033 M

Therefore [B] at equilibrium = 2(0.0033) = 0.0066 M


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