Question

In: Statistics and Probability

Let x be a random variable representing percentage change in neighborhood population in the past few...

Let x be a random variable representing percentage change in neighborhood population in the past few years, and let y be a random variable representing crime rate (crimes per 1000 population). A random sample of six Denver neighborhoods gave the following information.

x 31 1 11 17 7 6
y 177 39 132 127 69 53

In this setting we have Σx = 73, Σy = 597, Σx2 = 1457, Σy2 = 73,973, and Σxy = 9938.

What percentage of variation in y is explained by the least-squares model? (Round your answer to one decimal place.)

Find or estimate the P-value of the test statistic.

P-value > 0.2500.125 < P-value < 0.250    0.100 < P-value < 0.1250.075 < P-value < 0.1000.050 < P-value < 0.0750.025 < P-value < 0.0500.010 < P-value < 0.0250.005 < P-value < 0.0100.0005 < P-value < 0.005P-value < 0.0005


Conclusion

Reject the null hypothesis, there is sufficient evidence that ρ differs from 0.Reject the null hypothesis, there is insufficient evidence that ρ differs from 0.    Fail to reject the null hypothesis, there is sufficient evidence that ρ differs from 0.Fail to reject the null hypothesis, there is insufficient evidence that ρ differs from 0.


(e) For a neighborhood with x = 24% change in population in the past few years, predict the change in the crime rate (per 1000 residents). (Round your answer to one decimal place.)
crimes per 1000 residents

(f) Find Se. (Round your answer to three decimal places.)
Se =

(g) Find an 80% confidence interval for the change in crime rate when the percentage change in population is x = 24%. (Round your answers to one decimal place.)

lower limit     crimes per 1000 residents
upper limit     crimes per 1000 residents


(h) Test the claim that the slope β of the population least-squares line is not zero at the 1% level of significance. (Round your test statistic to three decimal places.)

t =



Find or estimate the P-value of the test statistic.

P-value > 0.2500.125 < P-value < 0.250    0.100 < P-value < 0.1250.075 < P-value < 0.1000.050 < P-value < 0.0750.025 < P-value < 0.0500.010 < P-value < 0.0250.005 < P-value < 0.0100.0005 < P-value < 0.005P-value < 0.0005


Conclusion

Reject the null hypothesis, there is sufficient evidence that β differs from 0.Reject the null hypothesis, there is insufficient evidence that β differs from 0.    Fail to reject the null hypothesis, there is sufficient evidence that β differs from 0.Fail to reject the null hypothesis, there is insufficient evidence that β differs from 0.


(i) Find an 80% confidence interval for β and interpret its meaning. (Round your answers to three decimal places.)

lower limit    
upper limit    


Interpretation

For every percentage point increase in population, the crime rate per 1,000 increases by an amount that falls outside the confidence interval.For every percentage point decrease in population, the crime rate per 1,000 increases by an amount that falls outside the confidence interval.    For every percentage point decrease in population, the crime rate per 1,000 increases by an amount that falls within the confidence interval.For every percentage point increase in population, the crime rate per 1,000 increases by an amount that falls within the confidence interval.

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