Question

In: Chemistry

Calculate the mass of water produced when 6.39 g of butane reacts with excess oxygen

Calculate the mass of water produced when 6.39 g of butane reacts with excess oxygen

Solutions

Expert Solution

2C4H10 + 13O2 ---------> 8CO2 + 10H2O
Molar mass of butane = 58.12 g/mol
mass of butane = 6.39 g
number of moles of butane = mass / molar mass
                                                          = 6.39 / 58.12
                                                          =0.11 mol

2 mol of butane produces 10 mol of H2O
so mol of H2O produce = 5 * number of moles of butane
                                                = 5* 0.11
                                                 = 0.55 mol

Molar mass of H2O = 18 g/mol
mass of water = molar mass * number of moles
                             = 18*0.55
                             = 9.9 g
Answer: 9.9 g

queen_honey_blossom answered 1 hour ago
Next > < Previous

Related Solutions

1. Calculate the mass of water produced when 5.13 g of butane reacts with excess oxygen....
1. Calculate the mass of water produced when 5.13 g of butane reacts with excess oxygen. Express your answer to three significant figures and include the appropriate units. 2. Calculate the mass of butane needed to produce 94.2 g of carbon dioxide. Express your answer to three significant figures and include the appropriate units.
Part A) Calculate the mass of water produced when 6.23 g of butane reacts with excess...
Part A) Calculate the mass of water produced when 6.23 g of butane reacts with excess oxygen. Part B) Calculate the mass of butane needed to produce 78.5 g of carbon dioxide. Part C) A sample of sodium reacts completely with 0.355 kg of chlorine, forming 585 g of sodium chloride. What mass of sodium reacted? Part D) When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 27.6 g of carbon were burned in...
451.4 g of lead reacts with excess oxygen forming 377.0 g of lead(II) oxide. Calculate the...
451.4 g of lead reacts with excess oxygen forming 377.0 g of lead(II) oxide. Calculate the percent yield of the reaction.
What is the mass of each product when 150.0 g of pentene (C5H10) reacts with excess...
What is the mass of each product when 150.0 g of pentene (C5H10) reacts with excess oxygen?
In the following reaction, 451.4 g of lead reacts with excess oxygen forming 321.9 g of...
In the following reaction, 451.4 g of lead reacts with excess oxygen forming 321.9 g of lead(II) oxide. Calculate the percent yield of the reaction. 2Pb(s)+O2(g)-->2PbO(s)
The gas butane, C4H10(g), can be used in welding. When butane is burned in oxygen, the...
The gas butane, C4H10(g), can be used in welding. When butane is burned in oxygen, the reaction is: 2 C4H10(g) + 13 O2(g) ---> 8 CO2(g) + 10 H2O(g) (a) Using the following data, calculate ΔH° for this reaction. ΔH°f kJ mol-1: C4H10(g) = -125.7; CO2(g) = -393.5 ; H2O(g) = -241.8 ΔH° = ______ (b) Calculate the total heat capacity of 8 mol of CO2(g) and 10 mol of H2O(g), using CCO2(g) = 37.1 J K-1 mol-1 and CH2O(g)...
A 5 g mixture of ethanol (C2H5OH) and methanol (CH3OH) reacts with excess oxygen. If this...
A 5 g mixture of ethanol (C2H5OH) and methanol (CH3OH) reacts with excess oxygen. If this combustion releases 125.46 kJ of heat, what mass of ethanol is in the mixture? Assume that mixing does not affect any enthalpy values. C2H5OH(l) + 3 O2(g) --> 2 CO2(g) + 3 H2O(g)    -277.63                              -393.5    -241.83 (kJ/mol) CH3OH(l) + 1.5 O2(g) -->   CO2(g) + 2 H2O(g)    -201.2                              -393.5    -241.83 (kJ/mol)
1. Butane, C4H10, reacts with oxygen, O2, to form water, H2O, and carbon dioxide, CO2, as...
1. Butane, C4H10, reacts with oxygen, O2, to form water, H2O, and carbon dioxide, CO2, as shown in the following chemical equation: 2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g) Calculate the mass of butane needed to produce 71.5 g of carbon dioxide. 2. For the reaction, calculate how many grams of the product form when 22.4 g of Ca completely reacts. Assume that there is more than enough of the other reactant. Ca(s)+Cl2(g)→CaCl2(s) 3. For the reaction, calculate how many grams of the product form when...
Butane, C4H10, reacts with oxygen, O2, to form water, H2O, and carbon dioxide, CO2, as shown...
Butane, C4H10, reacts with oxygen, O2, to form water, H2O, and carbon dioxide, CO2, as shown in the following chemical equation: 2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g) The coefficients in this equation represent mole ratios. Notice that the coefficient for water (10) is five times that of butane (2). Thus, the number of moles of water produced is five times the number of moles of butane that react. Also, notice that the coefficient for butane (2) is one-fourth the coefficient of carbon dioxide (8). Thus,...
Butane, C4H10, reacts with oxygen, O2, to form water, H2O, and carbon dioxide, CO2, as shown...
Butane, C4H10, reacts with oxygen, O2, to form water, H2O, and carbon dioxide, CO2, as shown in the following chemical equation: 2C4H10(g)+13O2(g)→10H2O(g)+8CO2(g) a) Calculate the mass of water produced when 2.04 g of butane reacts with excess oxygen. b) Calculate the mass of butane needed to produce 72.8 g of carbon dioxide.
ADVERTISEMENT
Subjects
ADVERTISEMENT
Latest Questions
ADVERTISEMENT