In: Chemistry
| Volume of .010 M CoClPr3 added/mL | Total Volume of Solution mL | Total moles CoClPr3 added/ mols | [CoClPr3]/(mols/L) |
| .10 | |||
| .20 | |||
| .30 | |||
| .40 | |||
| .50 | |||
| .60 | |||
| .70 | |||
| .80 | |||
| .90 | |||
| 1.00 | |||
| 1.10 |
The calibration plot is implemented by adding .10 mL increments of .010 M CoClPr3 to 4.00 mL of Pr in a cuvette. Calculate the given concentration, a table has been given to help with calculations.
moles = molarity x volume
molarity of solution = moles/total volume of solution
So for say 0.1 ml of 0.01M addition of CoClPr3 to 4 ml of Pr in a cuvette
moles of CoClPr3 = 0.01 x 0.0001 = 1 x 10^-6 mol
Total volume of solution = 4 + 0.1 = 4.1 ml = 0.0041 L
CoClPr3 concentration = 1 x 10^-6/0.0041 = 2.44 x 10^-4 mol/L
So we do rest of calculations following the same principle as shown above.
Table :
V 0.01 M CoClPr3(ml) total Vol(ml) moles of CoClPr3 CoClPr3(mol/L)
0.1 4.1 1 x 10^-6 2.44 x 10^-4
0.2 4.2 2 x 10^-6 4.76 x 10^-4
0.3 4.3 3 x 10^-6 6.98 x 10^-4
0.4 4.4 4 x 10^-6 9.10 x 10^-4
0.5 4.5 5 x 10^-6 1.11 x 10^-3
0.6 4.6 6 x 10^-6 1.30 x 10^-3
0.7 4.7 7 x 10^-6 1.49 x 10^-3
0.8 4.8 8 x 10^-6 1.67 x 10^-3
0.9 4.9 9 x 10^-6 1.84 x 10^-3
1.0 5.0 1 x 10^-5 2.00 x 10^-3
1.1 5.1 1.1 x 10^-5 2.16 x 10^-3