In: Statistics and Probability
A random sample of 81 lighting flashes in a certain region resulted in a sample average radar echo duration of 0.8168 sec and a sample standard deviation of 0.36 sec (“Lighting Strikes to an Airplane in a Thunderstorm”, Journal of Aircraft, 1984). Calculate a 99% (two-sided) confidence interval for the true average echo duration μ.
Solution :
Given that,
Point estimate = sample mean =
= 0.8168 sec
sample standard deviation = s = 0.36 sec
sample size = n = 81
Degrees of freedom = df = n - 1 = 81 - 1 = 80
At 99% confidence level the t is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
t
/2,df = t0.005,80 = 2.639
Margin of error = E = t/2,df
* (s /
n)
= 2.639 * (0.36 /
81)
= 0.1056
The 99% confidence interval estimate of the population mean is,
- E <
<
+ E
0.8168 - 0.1056 <
< 0.8168 + 0.1056
0.7112 <
< 0.9224
(0.7112 , 0.9224)