An elevator is descending with uniform acceleration.To measure the acceleration, a person in the elevator drops...

An elevator is descending with uniform acceleration.To measure the acceleration, a person in the elevator drops a coin at the moment the elevator starts.The coin is 6ft above the floor of the elevator at the time it is dropped.The person observes that the coin strikes the floor in 1 second. Calculate from these data the acceleration of the elevator

Expert Solution

The coin is dropped at the instant when evrything is at standstill .
the coin drops after one sec that means distance covered by coin
S=ut+1/2gt^2
S=0x1+1/2x9.8x1=4.9 m
but the distance to floor was only 1.82m(6ft) that means the elevator moved 4.9-1.82=3.07m in that one second.
So substituting this S again we have
S=ut+1/2at^2 (where a is the acceleration of elevator)
3.07=0+1/2*a*1
a=6.14m/sec^2
Thsi should be the answer..

genius_generous answered 2 years ago

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