Question

In: Math

Assume the following for a paired-samples t test: N = 19, Mdifference = 13.19, s =...

Assume the following for a paired-samples t test: N = 19, M_difference = 13.19, s = 22.3. What is the 95 percent confidence interval for a two-tailed test?

	A.	[8.07, 18.31]
	B.	[11.09, 15.29]
	C.	[–10.76, 10.76]
	D.	[2.44, 23.94]

Expert Solution

Solution :

Given that,

Point estimate = sample mean = = 13.19

sample standard deviation = s = 22.3

sample size = n = 19

Degrees of freedom = df = n - 1 = 19 - 1 = 18

At 95% confidence level the t is ,

= 1 - 95% = 1 - 0.95 = 0.05

/ 2 = 0.05 / 2 = 0.025

t_/2,df = t_0.025,18 = 2.101

Margin of error = E = t_/2,df * (s / $\sqrt$ n)

= 2.101 * (22.3 / $\sqrt$ 19)

= 10.75

The 95% confidence interval estimate of the population mean is,

- E < < + E

13.19 - 10.75 < <13.19 + 10.75

2.44 < < 23.94

(2.44 , 23.94)

milcah answered 1 hour ago

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