In: Economics
Assume that a production function is given by y = AK^1/3 L^2/3. If A = 6 and L = 1, the depreciation rate is 0.15, and the savings rate is 0.4, the steady-state level of capital is?
Putting the value of L=1 and A=6 in the production function we get :
y=6K^1/2
Investment function= sy
=0.4*6K^1/2.......... (1)
Depreciation= depreciation rate* capital stock
=0.15*K .............(2)
At steady state equation (1)=(2)
Therefore, 2.4K^1/2 = 0.15K
Or, 2.4/0.15=K^1/2
Or, K^1/2= 16
Or, K= 256. ( Ans)