In: Statistics and Probability
This table represents the avg weekly U.S. dollar wages for state employees and federal employees for 10 years. Construct and interpret a 90% prediction interval for the average weekly wages of federal employees when the avg weekly wages for state employees is $880. Round to nearest cent if needed.
Equation of regression line is y = 1.370x + 34.950
Wages (state), x | 703 | 766 | 788 | 820 | 856 | 872 | 926 | 931 | 938 | 970 |
Wages (federal), y | 1029 | 1064 | 1103 | 1152 | 1194 | 1253 | 1273 | 1301 | 1326 | 1398 |
1) There is 90% chance that predicted avg weekly wages of federal employees is between ($??) and ($??), given a state avg weekly wage of $880.
2) We can be 90% confident that when the avg weekly wages of state employees is $880, the avg weekly wages of federal employees will be between ($??) and ($??)
Q1. The prediction interval for an individual response when the predictor is is
where
, ,n is the total no of observation and k is the no of variable, = 1.860 is the tabulated t at (n-2) degree of freedom.
Now
calculation for Se is given below in the table
Wages (state), x | Wages (federal), y | ||
703 | 1029 | 998.06 | 957.2836 |
766 | 1064 | 1084.37 | 414.9369 |
788 | 1103 | 1114.51 | 132.4801 |
820 | 1152 | 1158.35 | 40.3225 |
856 | 1194 | 1207.67 | 186.8689 |
872 | 1253 | 1229.59 | 548.0281 |
926 | 1273 | 1303.57 | 934.5249 |
931 | 1301 | 1310.42 | 88.7364 |
938 | 1326 | 1320.01 | 35.8801 |
970 | 1398 | 1363.85 | 1166.2225 |
4505.284 |
90% prediction interval is .
Q2.)
90% Confidence interval is