In: Statistics and Probability
Suppose the length of textbooks in a library follows a bimodal distribution with a little right skewness (very mild). The mean of this distribution is 512 pages with a standard deviation of 390 pages.
For each of the following i) draw a picture. ii) label the picture with 2 axes (underneath). iii) label the shorthand for the new distribution. iv) Find the z-score. v) Find the answer.
a1) What is the probability that a random sample of 36 textbooks has an average of 445.2 pages or less?
a2) What is the probability that a random sample of 49 textbooks has an average higher than 613.3 pages?
a3) What is the probability that a random sample of 30 textbooks has an average number of pages between 400 and 500?
a4) Do you think you could answer a1 - a4 with a sample of just 2 textbooks? Why or why not?
Please note I have used z-distribution table for calculating p-value so answers may be less accurate because z value has to be rounded off to 2 decimal places. Use of calculator provides more accuracy. There may be slight difference in answer. I have provided both answers as nothing is mentioned which method has to be used.
Answer a1)
Mean of Sampling distribution μx̄ = Population mean = 512
Standard deviation of sampling distribution σx̄ = σ/sqrt(n) = 390/sqrt(36) = 390/6 = 65
The probability that a random sample of 36 textbooks has an average of 445.2 pages or less is 0.1515
Please note that answer with calculator will be 0.1520
Answer a2)
Mean of Sampling distribution μx̄ = Population mean = 512
Standard deviation of sampling distribution σx̄ = σ/sqrt(n) = 390/sqrt(49) = 390/7 = 55.7143
The probability that a random sample of 49 textbooks has an average higher than 613.3 pages is 0.0344
Please note that answer with calculator will be 0.0345
Answer a3)
Mean of Sampling distribution μx̄ = Population mean = 512
Standard deviation of sampling distribution σx̄ = σ/sqrt(n) = 390/sqrt(30) = 390/5.4772 = 71.2039
Probability that a random sample of 30 textbooks has an average no. of pages between 400 & 500 is 0.3743
Please note that answer with calculator will be 0.3752
Answer a4)
No, we could not answer a1 - a4 with a sample of just 2 textbooks. This is because as per central limit theorem for sampling distribution to be assumed normal, sample size should be 30 or more.