Pay attention to the ratio. An acid of pKa = 8.0 is present in a solution...

Pay attention to the ratio. An acid of pKa = 8.0 is present in a solution with a pH of 6.0. What is the ratio of protonated to the deprotonated form of the acid? Show your work

Expert Solution

According to Henderson-Hasselbalch equation,
pH = pKa + log [A-]/[HA]

Given values are pH = 6, pKa = 8

By substituting the values we get,

6 = 8 + log [A-]/[HA]
log [A-]/[HA] = -2

[A-]/[HA] = antilog (-2)

= 0.01

But according to question we need protonated to deprotonated ratio [HA]/[A-]

[HA]/[A-] = 1/0.01

[HA]/[A-] = 100

queen_honey_blossom answered 2 years ago

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