Question
In: Physics
A rotating cylindrical rod of mass m=4 Kg and length l=1 meter is connected to a...
A rotating cylindrical rod of mass m=4 Kg and length l=1 meter is connected to a falling weight of 300 grams with a 2 meters string (Maximum distance covered by the falling weight). The distance from the wound string to the axis of rotation is 300 mm. The time taken by the falling weight to halfway is 2 seconds and to the bottom is 3.7 seconds.
- Calculate the angular momentum of the rod at both the points .
- Explain the difference in the angular momentum at two points.
Solutions
genius_generous answered 2 years agoRelated Solutions
LAB QUESTION A rotating cylindrical rod of mass m=4 Kg and length l=1 meter is connected...
LAB QUESTION
A rotating cylindrical rod of mass m=4 Kg and length l=1 meter
is connected to a falling weight of 300 grams with a 2 meters
string (Maximum distance covered by the falling weight). The
distance from the wound string to the axis of rotation is 300 mm.
The time taken by the falling weight to halfway is 2 seconds and to
the bottom is 3.7 seconds.
Change of angular momentum in the spinning rod
Mass (Kg)
Moment of...
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A thin, cylindrical rod ℓ = 27.0 cm long with a mass m = 1.20 kg...
A thin, cylindrical rod ℓ = 27.0 cm long with a mass m
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M = 2.00 kg attached to one end. The arrangement is
originally vertical and stationary, with the ball at the top as
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the bottom end of the rod after being given a slight nudge.
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