Question

In: Chemistry

he chromatogram below is for a solution containing a mixture of limonene and cymene, two naturally-occurring...

he chromatogram below is for a solution containing a mixture of limonene and cymene, two naturally-occurring compounds found in lemon peel.

Limonene and cymene are present in an unknown proportion, so enough chlorobenzene is added to make its concentration in the solution equal to 0.0025 M.

Given that chlorobenzene has the lowest boiling point, and cymene has the highest boiling point, use the provided information to calculate the concentration of limonene in the mixture in moles per liter.

Peak	Area
A	176
B	2032.5
C	629.8

Expert Solution

The chromatogram below is for a solution containing a mixture of limonene and cymene, two naturally-occurring compounds found in lemon peel.

Limonene and cymene are present in an unknown proportion, so enough chlorobenzene is added to make its concentration in the solution equal to 0.0025 M.

Given that chlorobenzene has the lowest boiling point, and cymene has the highest boiling point, use the provided information to calculate the concentration of limonene in the mixture in moles per liter.

Peak Area

A 176

B 2032.5

C 629.8

Solution:

As the limonene has intermediate boiling point, its peak area will be the one in middle. The peak C represents limonene.

Peak area of limonene is 629.8.

% of limonene in solution is = 629.8/(629.8+2032.5+176) = 22.18%

% of limonene in respect to cymene = 629.8/(629.8+2032.5) = 23.65%

Concentration of limonene and cymene in solution is 0.0025 M, of which 23.65% is limonene.

So its 23.65 * 0.0025 M = 0.0591 moles/liter

queen_honey_blossom answered 2 years ago

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