Question

In: Math

According to an airline, flights on a certain route are on time 75% of the time

According to an airline, flights on a certain route are on time 75% of the time. Suppose 24 flights are randomly selected and the number of on-time flights is recorded. 

(a) Explain why this is a binomial experiment. 

(b) Find and interpret the probability that exactly 15 lights are on time 

(c) Find and interpret the probability that fewer than 15 flights are on time 

(d) Find and interpret the probability that at least 15 fights are on time. 

(e) Find and interpret the probability that between 13 and 15 flights, inclusive, are on time. 


(a) Identity the statements that explain why this is a binomial experiment Select all that apply. 

A. Each trial depends on the previous trial 

B. The experiment is performed a foved number of times 

C. The experiment is performed until a desired number of successes is reached 

D. There are two mutually exclusive outcomes, success or failure. 

E. The trials are independent 

F. The probability of success is the same for each trial of the experiment 

G. There are three mutually exclusive possibly outcomes, arriving on-time, arriving early, and arriving late 


(b) The probability that exactly 15 flights are on time is _______ (Round to four decimal places as needed)

 Interpret the probability 

in 100 trials of this experiment, it is expected about _______  to exactly than 15 fights being on time


(c) The probability that fewer than 15 flights are on time is _______ (Round to four decimal places as needed.) 

Interpret the probability 

in 100 trials of this experiment, it is expected about _______ to result in fewer than 15 fights being on time 


(d) The probability that at least 15 fights are on time is _______ (Round to four decimal places as needed) 

Interpret the probability 

in 100 trials of this experiment, it is expected about _______ to result in at least 15 nights being on time

Solutions

Expert Solution

given n = 24 p=0.75 fixed DJ There are two mutually failure =1 X ₂ Bir in, pa PCX=21)= ( pcr-box=0, I,.. n. The expeziment is


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