In: Statistics and Probability
Use the following vertical jump scores to develop a five
category evaluation scale (Excellent = .88s and above, Good = .28 -
.87s, etc.). Calculate the scores for each category (round to the
nearest tenth) and the number of subjects that scored within each
category. Round the mean and standard deviation to the nearest
tenth. The vertical jump scores are as follows: 22, 28, 27.5, 25,
29, 25, 30, 24, 24, 24, 27.5, 32.5, 26, 23, 22.5, 29.5, 22.5, 25,
25, 35, 31.5, 27.5, 25.5, 22.5, 28.5, 27.
Mean _____
Standard Deviation _____
Grading Scale # of Students Receiving Grade
Excellent ______ to ______
______
Good ______ to ______ ______
Average ______ to ______ ______
Fair ______ to ______ ______
Poor ______
to ______ ______
The mean of the data sample is calculated as:
Mean = (22 + 28 + 27.5 + 25 + 29 + 25 + 30 + 24 + 24 + 24 + 27.5
+ 32.5 + 26 + 23 + 22.5 + 29.5 + 22.5 + 25 + 25 + 35 + 31.5 + 27.5
+ 25.5 + 22.5 + 28.5 + 27)/26
= 689.5/26
Mean = 26.5
and the standard deviation as;
Standard Deviation σ = √(1/26 - 1) x ((22 - 26.5192)2 +..........................................+ ( 27 - 26.5192)2)
= √(1/25) x ((-4.5192)2 + ......................................................... + (0.4808)2)
= √(0.04) x ((20.42316864) + .................................................. + (0.23116864))
= √(0.04) x (279.74038464)
= √(11.1896153856)
= 3.3451
= 3.3
The grading scale can be of any scale can be built as no specific scale is given, below is the grading scale where the digit value is the percentile score and the corresponding to the percentile score the Z score can be calculated using the Z table shown below, further using the Z score formula the scores that fall under the category can be calculated.
The Z score formula is :
Grading Scale
no of Students Receiving Grade
Excellent : 0.80 to above
Good : 0.70 to
0.80
Average : 0. 60 to
0.70
Fair : 0.40 to
0.60
Poor : 0. 40 to
below
The Z table that can be used to find the Z score, please see the marked value as an example for an Excellent grading scale for percentile more than 0.80.