Question

In: Chemistry

(-)-Mandelic acid has a specific rotation of -158°. What would be the specific rotation of a...

(-)-Mandelic acid has a specific rotation of -158°. What would be the specific rotation of a solution which contains 40% (-)-mandelic acid and 60% (+)-mandelic acid?

+95°
-32°
-63°
+63°
+32°

Solutions

Expert Solution

Given the % of (-)-mandelic acid is 40%

its specific rotation = -158o

Given the % of (+)-mandelic acid is 60%

its specific rotation = +158o

The specific rotation of the solution = (% of - rotation x its percentage)+(% of + rotation x its percentage)

                                                   = [(40/100)x(-158) ] + [(60/100) x (+158)]

                                                   = +32 o


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