Calculate specific rotation, %ee, and %R and %S using the data below Mass of product: 0.171...

Calculate specific rotation, %ee, and %R and %S using the data below

Mass of product: 0.171 g

Volume of solution: 5.00 mL

Path length: 1.000 dm

Observed rotation: 0.95

Thanks !!

Expert Solution

given mass of product = 0.171g

volume of solution = 5mL

path length l= 1dm

observed rotation = 0.95^o

now, 0.171g in 5 mL solution c= 0.0342g/mL

specific rotation is given by []=/cl= 0.95/0.0342x1=27.77^o

enantiomeric excess (ee%) is given by : ee%= /[]x 100=0.95/27.77x 100=3.42% i.e. there is a 3.42% excess of R over S. this corresponds to a mixture of 51.71% of R and 48.29% of S

%R=51.71%

%S=48.29%

queen_honey_blossom answered 2 years ago

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