In: Finance
This problem is a complex financial problem that requires
several skills, perhaps some from previous sections.
During four years of college, Nolan MacGregor's student loans are
$4000, $3500, $4400, and $5000 for freshman year through senior
year, respectively. Each loan amount gathers interest of 1.6%,
compounded quarterly, while Nolan is in school and 3.9%, compounded
quarterly, during a 6-month grace period after graduation.
(a) What is the loan balance after the grace period? Assume the
freshman year loan earns 1.6% interest for 3/4 year during the
first year, then for 3 full years until graduation. Make similar
assumptions for the loans for the other years. (Round your answer
to the nearest cent.)
$
(b) After the grace period, the loan is amortized over the next 10
years at 3.9%, compounded quarterly. Find the quarterly payment.
(Round your answer to the nearest cent.)
$
(c) If Nolan decides to pay an additional $80 per payment, how many
payments will amortize the debt? (Round your answer up to the next
whole number.)
quarters
(d) How much will Nolan save by paying the extra $80 with the
number of payments from part (c)? (Round your answer to the nearest
cent.)
$
(a) What is the loan balance after the grace period? Assume the freshman year loan earns 1.6% interest for 3/4 year during the first year, then for 3 full years until graduation. Make similar assumptions for the loans for the other years.
=(4000*(1+1.6%/4)^3*(1+1.6%/4)^12+3500*(1+1.6%/4)^3*(1+1.6%/4)^8+4400*(1+1.6%/4)^3*(1+1.6%/4)^4+4000*(1+1.6%/4)^3)*(1+3.9^/4)^2=16799.70032
(b) After the grace period, the loan is amortized over the next 10 years at 3.9%, compounded quarterly. Find the quarterly payment. (Round your answer to the nearest cent.)
=PMT(3.9%/4,4*10,16799.7032)=$509.22
(c) If Nolan decides to pay an additional $80 per payment, how many payments will amortize the debt?
=NPER(3.9%/4,-509.22-80,16799.7032)=33.57 quarters or 36 payments or 9 years
(d) How much will Nolan save by paying the extra $80 with the number of payments from part (c)?
=(509.22+80)*36-509.22*40=843.12