Data was collected to study the background of the people who participate in online gambling. 64...

Data was collected to study the background of the people who participate in online gambling. 64 people were selected at random and asked about their annual salary and whether they went to college. After the survey, sample mean and sample standard deviation were calculated. They were $90K and $30K respectively. A. Calculate 95% confidence limits for the population mean annual salary. B. What is the interpretation of the limits in part A? C. If you calculate 99% confidence limits for the population mean annual salary, will the confidence interval be wider or narrower? Explain your answer.

Expert Solution

orchestra answered 2 years ago

Data was collected to study the background of the people who participate in online gambling. Data...

Data was collected to study the background of the people who participate in online gambling. Data was collected to study the background of the people who participate in online gambling. Data was collected to study the background of the people who participate in online gambling. Data was collected to study the background of the people who participate in online gambling. Data was collected to study the background of the people who participate in online gambling. Data was collected to study...

1. In preparing to do a study on the proportion of people who use internet gambling...

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Data for 64 female college athletes was collected. The data on weight (in pounds) are roughly...

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data were collected on the amount spent by 64 consumers for lunch at a major Houston...

data were collected on the amount spent by 64 consumers for lunch at a major Houston restaurant. these data are contained in the file named Houston. based upon past studies the population standard deviation is known with $9. a. at 99% confidence, what is the margin of error? $_ b. develop a 99% confidence interval estimate of the mean amount spent for lunch? $_ to $_ Amount 20.50 14.63 23.77 29.96 29.49 32.70 9.20 20.89 28.87 15.78 18.16 12.16 11.22...

Data were collected on the amount spent by 64 customers for lunch at a major Houston...

Data were collected on the amount spent by 64 customers for lunch at a major Houston restaurant. Based upon past studies the population standard deviation is known with $6. Round your answers to 2 decimal places. Use the critical value with 3 decimal places. At 99% confidence, what is the margin of error? Develop a 99% confidence interval estimate of the mean amount spent for lunch. Amount 20.50 14.63 23.77 29.96 29.49 32.70 9.20 20.89 28.87 15.78 18.16 12.16 11.22...

Data were collected on the amount spent for lunch by 64 customers at a major Houston...

Data were collected on the amount spent for lunch by 64 customers at a major Houston restaurant. The sample provided a sample mean of $21.5. Based upon past studies the population standard deviation is known with σ = $6. Develop a 99% confidence interval estimate of the mean amount spent for lunch.

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