Using C++. Implement l_list.cpp and l_list.h

l_list and encounterNode. The former is a richly featured linked list with a wide variety of methods and the latter is a node meant to encapsulate a game encounter. In the context of this task, the encounterNode represents a battle encounter. Each encounter will describe what a player has to watch in the course of the level in terms of enemies, rewards and such. Therefore a combination of encounterNodes contained within a linked list would represent a single level in a game. The classes and behaviors of their methods are detailed below:

l_list
-head: encounterNode*
---------------------------
+l_list()
+~l_list()
+addToFront(a:string*, b:int, c:string):int
+addToBack(a:string*, b:int, c:string):int
+addAtIndex(a:string*, b:int, c:string, index:int):int
+getListSize():int
+removeFromFront():encounterNode*
+removeFromBack():encounterNode*
+removeFromIndex(index:int):encounterNode*
+printSummaryOfList():void
+printList():void

The class has the following variables:
•head: The head pointer which demarcates the start of the list.

The class has the following methods:
•l_list: The list constructor. It will start by initialising a blank list with no elements.

•∼l_list: The list destructor. It should delete all of the remaining nodes in the list and deallocate all of the memory contained within. After deleting the list, it should print out the following message: ”Number of nodes deleted: X” without quotation marks where X indicates the number of nodes deleted in the process. Be sure to add a newline at the end of this output.

•addToFront: This method receives the variables to construct a new node and then allocates memory for it before adding it to the list at the front. It returns the new size of the list, that is the size of the list with the added node.

•addToBack: This method receives the variables to construct a new node and then allocates memory for it before adding it to the list at the back of the list. It returns the new size of the list, that is the size of the list with the added node.

•addAtIndex: This method receives the variables required to instantiate a new node as well as an index. This method should insert this node into the list at the given index. If the given index is not contained within the list, such as inserting at 5 when the list is only 2 nodes big, instead you must add it to the front. Note that the list is 0-indexed. It returns the new size of the list, that is the size of the list with the added node.

•getListSize: This method determines the number of nodes in the list and returns this as an integer.

•removeFromFront: This remove method removes a node from the list from the front and returns it. Note that the node is returned and not deleted; it must be properly unlinked from the list without being destroyed. If the list is empty, return NULL.

•removeFromBack: This remove method removes a node from the list from the back and returns it. Note that the node is returned and not deleted; it must be properly unlinked from the list without being destroyed. If the list is empty, return NULL.

•removeFromIndex: This method receives an index of a node to remove from the list. This node must be removed and returned without being destroyed; that is, unlinked from the list without being deleted. Note that if the index is not valid or the list is empty then the method should return NULL. The list is 0-indexed.

•printList: This method prints out the entire list, starting from the front. If the list is empty, print ”EMPTY LIST” without the quotation marks and a newline at the end. The example output is given below:
       Node 0
       Number of Enemies: 2
       Reward: Boots of Healing
       Enemy 1: Imp
       Enemy 2: Imp
       Node 1
       Number of Enemies: 2
       Reward: Sword of Revealing Light
       Enemy 1: Mancubus
       Enemy 2: Hell Knight

•printSummaryOfList: This method is a more sophisticated type of print. Instead of merely printing out of the full information of the list, it aggregates and collates the information from the list into a more easily readable report. If the list is empty,
print ”EMPTY LIST” without the quotation marks and a newline at the end. The report determines the following pieces of information:
       1.The number of nodes in the list.
       2.The number of enemies, in total in the list.
       3.The number of rewards which are healing to the player, that is if the reward has Healing or Health in its name. You can assume that the case will match the specific form of Healing or Health.
Therefore the output of this print operation takes the form (considering the prior example as the list):

       Number of Nodes: 2
       Number of Enemies: 4
       Number of Healing Rewards: 1

You are only allowed the use of the following libraries: string and iostream.

===================encounterNode.h=====================

#ifndef ENCOUNTER_NODE_H
#define ENCOUNTER_NODE_H
#include<iostream>
#include<string>
using namespace std;

class encounterNode
{
   private:
       string* enemies;
       int numEnemies;
       string reward;
   public:
       encounterNode* next;
       encounterNode(string* list, int numE, string re);
       ~encounterNode();
       string* getEnemies() const;
       void setEnemies(string* a, int b);
       string getEnemyAtIndex(int a);
       void setEnemyAtIndex(int a, string b);
       string getReward() const;
       void setReward(string a);
       int getNumEnemies() const;
       void setNumEnemies(int a);
       void print();
};
#endif

===================encounterNode.cpp=====================

#include "encounterNode.h"
#include<iostream>
#include<string>
using namespace std;

encounterNode::encounterNode(string* list, int numE, string re)
{
   enemies = list;
   numEnemies = numE;
   reward = re;
}

encounterNode::~encounterNode()
{
   delete [] enemies;
}

string* encounterNode::getEnemies() const
{
   return enemies;
}

void encounterNode::setEnemies(string* a, int b)
{
   if (enemies != NULL)
       delete[]enemies;

   enemies = new string[b];
   for (int i = 0; i < b; i++)
       enemies[i] = a[i];

   numEnemies = b;
}

string encounterNode::getEnemyAtIndex(int a)
{
   if (a >= 0 && a < numEnemies)
       return enemies[a];
   else
       return "";
}

void encounterNode::setEnemyAtIndex(int a, string b)
{
   if (a >= 0 && a < numEnemies)
       enemies[a] = b;
}

string encounterNode::getReward() const
{
   return reward;
}

void encounterNode::setReward(string a)
{
   reward = a;
}

int encounterNode::getNumEnemies() const
{
   return numEnemies;
}

void encounterNode::setNumEnemies(int a)
{
   numEnemies = a;
}

void encounterNode::print()
{
   cout << "Number of Enemies: " << numEnemies << endl;
   cout << "Reward: " << reward << endl;
   for (int i = 0; i < numEnemies; i++)
   {
       cout << "Enemy " << (i + 1) << ": " << enemies[i] << endl;
   }
   cout << endl;
}

this won't compile

package com.test;

public class CatalogItem {

private String title;

private double price;

public CatalogItem(String title, double price) {

super();

this.title = title;

this.price = price;

}

public String getTitle() {

return title;

}

public double getPrice() {

return price;

}

}

//Book.java

package com.test;

public class Book extends CatalogItem {

private String author;

private int ISBN;

public Book(String title, double price, String author, int iSBN) {

super(title, price);

this.author = author;

ISBN = iSBN;

}

public String getAuthor() {

return author;

}

public int getISBN() {

return ISBN;

}

@Override

public String toString() {

return "Title: " + getTitle() + " | Author: "+author + " | Price: " + getPrice() + " ISBN: "+ISBN;

}

}

//AudioBook.java

package com.test;

public class AudioBook extends Book {

private double runningTime;

public AudioBook(String title, double price, String author, int iSBN, double runningTime) {

super(title, price, author, iSBN);

this.runningTime = runningTime;

}

public double getRunningTime() {

return runningTime;

}

public double getP() {

return getPrice()*0.90;

}

@Override

public String toString() {

return "Title: " + getTitle() + " | Author: "+getAuthor() + " | Price: " + getP() + " | ISBN: "+getISBN() + " | running time: "+runningTime;

}

}

//DVD.java

package com.test;

public class DVD extends CatalogItem {

private String director;

private int year;

private int dvdcode;

public DVD(String title, double price, String director, int year, int dvdcode) {

super(title, price);

this.director = director;

this.year = year;

this.dvdcode = dvdcode;

}

public String getDirector() {

return director;

}

public int getYear() {

return year;

}

public int getDvdcode() {

return dvdcode;

}

@Override

public String toString() {

return "Title: " + getTitle() + " | Director: "+director + " | Price: " + getPrice() + " | Year: "+year + " | DvdCode: "+dvdcode;

}

}

//Driver.java

package com.test;

import java.util.ArrayList;

import java.util.Scanner;

public class Driver {

public static ArrayList<Book> booklist = new ArrayList<>();

public static ArrayList<DVD> dvdlist = new ArrayList<>();

public static void display()

{

for(int i=0;i<booklist.size();i++)

{

if(booklist.get(i) instanceof AudioBook)

System.out.println((AudioBook)(booklist.get(i)));

else

System.out.println(booklist.get(i));

}

System.out.println("-------------------------------------------------------------------------------");

for(int i=0;i<dvdlist.size();i++)

{

System.out.println(dvdlist.get(i));

}

}

//method to find book

public static boolean findBook(int isbn)

{

for(int i=0;i<booklist.size();i++)

{

if(booklist.get(i).getISBN() == isbn)

return true;

}

return false;

}

//method to find book

public static boolean findDVD(int dvdcode)

{

for(int i=0;i<dvdlist.size();i++)

{

if(dvdlist.get(i).getDvdcode() == dvdcode)

return true;

}

return false;

}

public static void main(String[] args) {

System.out.println("Welcome to the comets Books and DVDs store(Catalog Section)");

int option;

String title;

double price;

String author;

int isbn;

double runningTime;

String director;

int year;

int dvdcode;

Scanner sc = new Scanner(System.in);

while (true) {

System.out.println("Choose from the following option:");

System.out.println("1-Add Book");

System.out.println("2-Add AudioBook");

System.out.println("3-Add DVD");

System.out.println("4-Remove Book");

System.out.println("5-Remove DVD");

System.out.println("6-Display Catalog");

System.out.println("9-Exit Store");

option = sc.nextInt();

if(option == 1)

{

System.out.println("Please enter Book isbn");

isbn = sc.nextInt();

if(findBook(isbn))

continue;

System.out.println("Please enter Book title");

title = sc.next();

System.out.println("Please enter Book price");

price = sc.nextDouble();

while(price < 0) {

System.out.println("Please enter Book valid price");

price = sc.nextDouble();

}

System.out.println("Please enter Book author");

author = sc.next();

Book b = new Book(title, price, author, isbn);

booklist.add(b);

}

else if(option == 2)

{

System.out.println("Please enter Audio Book isbn");

isbn = sc.nextInt();

if(findBook(isbn))

continue;

System.out.println("Please enter Audio Book title");

title = sc.next();

System.out.println("Please enter Audio Book price");

price = sc.nextDouble();

while(price < 0) {

System.out.println("Please enter Audio Book valid price");

price = sc.nextDouble();

}

System.out.println("Please enter Audio Book author");

author = sc.next();

System.out.println("Please enter Audio Book running time");

runningTime = sc.nextDouble();

while(runningTime < 0) {

System.out.println("Please enter Audio Book valid running time");

runningTime = sc.nextDouble();

}

AudioBook b = new AudioBook(title, price, author, isbn,runningTime);

booklist.add(b);

}

else if(option == 3)

{

System.out.println("Please enter DVD code");

dvdcode = sc.nextInt();

if(findDVD(dvdcode))

continue;

System.out.println("Please enter DVD title");

title = sc.next();

System.out.println("Please enter DVD price");

price = sc.nextDouble();

System.out.println("Please enter DVD director");

director = sc.next();

System.out.println("Please enter DVD year");

year = sc.nextInt();

DVD d = new DVD(title, price, director, year, dvdcode);

dvdlist.add(d);

}

else if(option == 4)

{

System.out.println("Enter isbn number to delete book");

isbn = sc.nextInt();

boolean remove = false;

for(int i=0;i<booklist.size();i++){

if(booklist.get(i).getISBN() == isbn){

booklist.remove(i);

remove = true;

}

}

if(remove == false)

System.out.println("The Book doesn't exist in catalog");

display();

}

else if(option == 5)

{

System.out.println("Enter dvd code to delete DVD");

dvdcode = sc.nextInt();

boolean remove = false;

for(int i=0;i<dvdlist.size();i++){

if(dvdlist.get(i).getDvdcode() == dvdcode){

dvdlist.remove(i);

remove = true;

}

}

if(remove == false)

System.out.println("The DVD doesn't exist in catalog");

display();

}

else if(option == 6)

{

display();

}

else if(option == 9)

break;

else

System.out.println("This option is not acceptable");

}

}

}

1. Write a program in java which store 10 numbers and find the sum of odd and even numbers.
2. Create a program that uses a two dimensional array that can store integer values inside. (Just create an array with your own defined rows and columns). Make a method called Square, which gets each of the value inside the array and squares it. Make another method called ShowNumbers which shows the squared numbers.
3. Write a program in java which has an array of 10 numbers, search whether the number 20 present in that array. If present replace it with 40.
4. Write a program in java which has an array of 10 numbers; insert the number 100 in the index position 3.
5. Write a program in java which has an array of 10 numbers; delete the number from the index position 5.
6. Write a program in java which has two arrays of size 4 and 5; merge them and sort.

1) Design an efficient data storage scheme using Normalization steps we have outlined.

2) Create tables as per normalization steps we have discussed in your database

Submit the table creation script and the output of desc

Explain any thing you wish to explain.

Data below:

invoiceno, invoice_date, invoice_amount, vendor, vendor_phone, vendor_address, vendor_preferred_payment_method,  verification_date, verified_by, verifier_code, verifier_role_title, approval_date, approved_by, approver_code, approver_role_title, payment_date, payment_by, payer_code, payer_title
211,10/19/2019,2311.45,VIC,673-234-4001,"blah blah,nyc,ny",check:made payable to VIC:net 30d,10/20/2019,Shelley Cramer,SC,ECOM:Project manager,10/20/2019,Zack Swindler,ZS,Sales:Managing Director,10/21/2019,Cathy Zuppa, CZ, Finance:CPA
209,10/10/2019,28750.07,GRC,913-123-3489,"zing zing, Cool,CO",ACH:ABA23457892 FBO GRC:net 30d,10/10/2019,Zack Swindler,ZS,Sales:Managing Director,10/11/2019,Tiny Bulger, TB, COO,10/12/2019,Irwine Ladder,IL,Finance:CFO
203,10/4/2019,17000.45,NightCrawler,873-318-7777,"Blue Lagoon,Torch,AZ",check:made payable to NCH:net 60d,10/7/2019,Zack Swindler,ZS,Sales:Managing Director,10/8/2019,Shelley  Cramer, SC, ECOM:Project Manager,10/12/2019,Cathy Zuppa, CZ, Finance:CPA
181,10/1/2019,2311.45,VIC,673-234-4001,"blah blah,nyc,ny",check:made payable to VIC:net 60d,10/2/2019,Zack Swindler,ZS,Sales:Managing Director,10/3/2019,Martin Short,MS,Sales:Managing Director,10/21/2019,Cathy Zuppa, CZ, Finance:CPA

Complete the following: (With Details and example if needed)

Given set S = {-3, -2, 0, 1, 2, 4}

Relation R is a relation on S such that R = { (?, ?) | ? ∈ ?, ? ∈ ? ??? ?? ≥ 1}

1. Using roster method, what is R?

2. Show the digraph representation of R

3. Show the matrix representation of R

4. if the relation does not have the property, give an example of why:

- Is R reflexive?

- Is R symmetric?

-Is R antisymmetric?

- Is R transitive?

A zombie picks up a calculator and starts adding odd whole numbers together, in order: 1 + 3 + 5......etc. You want to be able to determine the last number the zombie will add that will make the sum exceed some target number, such as "What will be the last number added that will make the sum on his calculator greater than 10,000?".

Write the MATLAB code necessary to solve this problem for the zombie or he will eat your brain. Create a function with an input of the target number (in the scenario given above the target number would be 10,000), which outputs the last numbered added.

Answer question in Python, show all code:

Write a program that calculates and displays the end of year balances in a savings account if $1,000 is put in the account at 6% interest for five years. For this problem, assume interest is calculated annually. (That is, if I put $1000 in a bank account at the beginning of the year, then the balance at the end of the year is $1,000 + $1,000*6%.) You may assume no money is removed from the account over this period.

Your program output should look like this:

Balance after year 1 is $ 1060.0

Balance after year 2 is $ 1123.6

Balance after year 3 is $ 1191.02

Balance after year 4 is $ 1262.48

Balance after year 5 is $ 1338.23

1. Sorting algorithm for arrays: understand how to perform the following algorithms. (a). Simple sorting

   1. Bubblesort:T(n)ÎO(n2)

   2. Selection sort : T(n) Î O(n2)

   3. Insertion sort: T(n) Î O(n2)

   (b).Advanced sorting

i. Shell sort: O(n2) < O(n1.25) < O(nlogn), O(n1.25) is empirical result for shell sort.

2. Merge sort: T(n) Î O(nlogn), need one temporary array with the same length as the array needed to be sorted.

3. Quick sort: -average case: T(n) Î O(nlogn),
   -worst case(rare occurrence): T(n) Î O(n2)

5. Searching algorithm for arrays: understand how to perform the following algorithms. (a). Searching in unsorted arrays

i. Sequentialsearch
ii. Sequential search with sentinel

(b).Searching in sorted arrays

1. Binary search

2. Interpolation search

Why do think understanding the OSI Model is important from a work standpoint? Give an example.

How can I make this not add to the counter when the guess is right?

void guessGenerator(string hangmanStar, string wordFromWordtxt)  
{

   char temp = '\0';
   bool win = false;
   int counter = 0;

   while ((win == false) || (counter == 7))
   {
       char temp;
       cout << hangmanStar << endl;
       cout << "? ";
       cin >> temp;
       counter++;

       for (int i = 0; i < wordFromWordtxt.length(); i++)
       {
           if (wordFromWordtxt.at(i) == temp)
           {
               hangmanStar.at(i) = temp;
           }
       }

       if (wordFromWordtxt == hangmanStar)
       {
           win = true;
           cout << "You win." << endl;
           cout << "The word was: " << hangmanStar << endl;
       }
       else if (counter == 7)
       {
           hangManPicture(counter);
           cout << endl;
           cout << "You lost" << endl;
           cout << "Answer: " << wordFromWordtxt << endl;
           return;
       }
       else
       {
           if (hangmanStar.find(temp) == string::npos)
           {
               cout << endl;
               cout << "Oops";
               hangManPicture(counter);
               cout << endl;
           }
           else
           {
               hangManPicture(counter);
               cout << endl;
           }          
       }
   }
   return;
}

Complete this programming problem in this assignment by using Microsoft Visual Studio Suite. Compile your solutions for each problem solved in a Word or Google document which includes (a) the pseudocode, (b) the C# codes and (c) the execution result (screen capture just the answer part using Snipping Tool, avoiding non-related or blank spaces). Notice for readability, that the (a) & (b) are in text mode and the (c) is in image mode. Use proper titles and wording in the results, such as Console.WriteLine("The total change to be made is {0:C}.", change); so that the results could be easily understood by a third party reader.

Question: Write a C# program to compute the profit made for selling goldfish flakes online. The wholesale cost for a case of 24-boxes is $118. The price for sale with shipping charge is $9.59 per box. Shipping cost is $1.35 per box. The onlinelisting charge is 12% of the customer payment. The payment processing cost is 4% of the payment. Compute and display the following figures for selling 25 cases of the products: the total wholesale cost for 25 cases; the total revenue for 25 cases of 24 boxes per case, the total listing cost, the total payment processing cost, and the total profit made.

• Write a JAVA program called DBConvertor that has two methods. The first one converts ANY user input binary into its equivalent decimal number. The second method converts ANY user input decimal number into its equivalent binary.​
• binaryToDecimal, decimalToBinary are the names for those methods.​
• binaryToDecimal receives a binary number as a string and returns a decimal number as an integer. And vice versa for the decimalToBinary method.​

1.  

(a)

1. We are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2*10⁸ meters/sec, and the distance between source and destination is 10,000 km. Now suppose that the MP3 file is broken into 3 packets, each of 10 Mbits. Ignore headers that may be added to these packets. Also ignore router processing delays. Assuming store and forward packet switching at the router, the total delay is ____.

(b) Review the car-caravan example in Section 1.4. Again assume a propagation speed of 100 km/hour. Suppose the caravan travels 200 km, beginning in front of one tollbooth, passing through a second tollbooth, and finishing just before a third tollbooth. Now suppose that when a car arrives at the second tollbooth, it proceeds through the tollbooth without waiting for the cars behind it. What is the end-to-end delay?

(c) We are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2*10⁸ meters/sec, and the distance between source and destination is 10,000 km. Now suppose there is only one link between source and destination, and there are 10 FDM channels in the link. The MP3 file is sent over one of the channels. The end-to-end delay is ____.

(d) We are sending a 30 Mbit MP3 file from a source host to a destination host. All links in the path between source and destination have a transmission rate of 10 Mbps. Assume that the propagation speed is 2*10⁸ meters/sec, and the distance between source and destination is 10,000 km. Now suppose there is only one link between source and destination. Also suppose that the entire MP3 file is sent as one packet. The transmission delay is ____.