All the answers must be in Binary format. As always please show all your work.

9.75 + 0.5625

125.125 * 12.0625

Single inheritance

Given two integer numbers N1 and N2, create a class 'ProblemSolution' with following characteristics.

1. Must extend a 'Base' class.
2. Create a method 'solution' with two integer parameters (N1 and N2) and long return type.
3. The 'solution' method should call the addition and subtraction methods of 'Base' class and return multiplication of returned results of addition and subtraction method.

Result = (N1 + N2) * (N1 - N2)

What is inheritance?
Inheritance is a mechanism in which one object acquires all the properties and behaviors of the parent object.
Reference: https://www.tutorialspoint.com/cplusplus/cpp_inheritance.htm

Input
    50
    10

Output
    2400

Given:

#include <iostream>
using namespace std;

// Base class
class Base {
public:
int addition(int N1, int N2) {
int result = N1 + N2;
return result;
}
  
int subtraction(int N1, int N2) {
int result = N1 - N2;
return result;
}
  

};

   //write your code here

int main() {
int N1;
int N2;
cin >> N1;
cin >> N2;
ProblemSolution problemSolution;
cout << problemSolution.solution(N1,N2);
return 0;
}

C++

Must Run:

Both numbers being 0

1 negative and 1 positive number

both negative numbers

Large numbers

Homework 4

Put all home works together and use methods to simplify code. Also expand to have preferences and budget for wall coverings the way that was done for floor options

Use separate Methods to calculate the change for each the Door, Window and Bookcase (Hint – you may want to use 2 methods for the book case effects since one is floor and other is wall).

The user shall input the dimensions of the room and the eventual output will be how the walls and flooring is done and how much budget is left.

The user will input the number of doors, windows, and bookcases and the dimensions of each which will be used to adjust the total wall and floor space needed to be covered. The system will output the square feet of wall and floor after adjustments.

The user will be asked for his budget for the walls and if he has a preference for the type of material for the wall. The system will accept as input the costs for the different wall coverings and determine which wall covering the user can afford – being either his preference or the most expensive if he does not have a preference. It’s also possible the user can not afford any wall coverings. The budget left after the wall covering is kept for how much money is left.

The system will output the initial budget for walls, the selected option and cost and what is left in the budget for walls.

The same process will work for floor coverings with the same output for flooring.

YOU also have COST OPTIONS FOR WALLS, A USER PREFERENCE AND A BUDGET, YOU WILL DO THE SAME FOR THE WALL. SAME RULES APPLY – IF 0 THEN JUST PICK MOST EXPENSIVE, IF PREFERENCE GIVE PREFERENCE IF CAN AFFORD, IF NOT GIVE WHAT CAN AFFORD.

There are four options for wall cover (Ceramic Tile = 1; Paneling = 2, Wallpaper = 3; and paint = 4) each with a cost per square foot The program will ask for input and read in the budget in dollars and cents, the cost per square foot for each of the different wall options and also ask for which one the customer prefers where 0 means the customer does not care and 1-4 if they have a specific preference.

Output the users preference, their budget, if they got their preference, and what they did get. Also how much budget is left.

You will be graded on how well you map this to methods and how good the comments are explaining what the program does.

Use the following for data (it is the same as HW 3 so you should get the same selection answers for flooring as you get there.

·         First renovation project (THREE DOORS, ONE BOOKSHELF, NO WINDOWS)

o    Room is 12 feet long, 12 feet wide, and 12 feet high

o    Door 1 is 2 feet wide by 10 feet high

o    Door 2 is 3 feet wide by 5 feet high

o    Door 3 is 3 feet wide by 5 feet high

o    Bookshelf is 8 feet long by 10 feet high by 2 feet deep

o    No windows

·         Second renovation project (3 WINDOWS, 2 BOOKSHELFS, NO DOORS)

o    Room is 24 feet long, 12 feet wide, and 8 feet high

o    Window 1 is 2 feet wide by 6 feet high

o    Window 2 is 3 feet wide by 5 feet high

o    Window 3 is 8 feet wide by 5 feet high

o    Bookshelf 1 is 8 feet long by 6 feet high by 3 feet deep

o    Bookshelf 2 is 3 feet long by 6 feet high by 2 feet deep

o    No doors

·         Third renovation project (ONE DOOR, 2 WINDOWSS, ONE BOOKSHELF)

o    Room is 12.75 feet long, 11.25 feet wide, and 12 feet high

o    Door is 1.95 feet wide by 10 feet high

o    Window 1 is 2.5 feet wide by 5 feet high

o    Window 2 is 6.8 feet wide by 7.2 feet high

o    Bookshelf is 8 feet long by 6 feet high by 3 feet deep

For Flooring use:

Tile= $4.00 /sq ft; Wood = $3.00/ sq ft; Carpet = $2.00/ sq ft and linoleum = $1.00/sq ft).

Use the following as the budget and preference:

There are four options for wall cover (Ceramic Tile = 1; Paneling = 2, Wallpaper = 3; and paint = 4) each with a cost per square foot

For all three test renovation projects use Tile= $4.00 /sq ft; Paneling = $3.00/ sq ft; Wallpaper = $2.00/ sq ft and paint = $1.00/sq ft).

Use the following as the budget and preference:

hw 3

package lab;

import static java.lang.System.*;
import java.util.Scanner;
// Renovation Project
public class hw3 {
{
}
public static void main(String args[]) {
double rheight, rwidth, rlength; //room height,width and length variabe
int numberOfDoors,numberOfWindows,numberOfBookCases=0;
double dheight=0, dwidth=0; //door height and width variable
double w1height, w1width;//window1 height and width variable
//double w2height, w2width;//window2 height and width variable
double bheight, bwidth, blength;//bookshelf height ,length and width variable
double paintArea, carpentArea, floorArea;
double paintCost, carpentCost = 0, floorCost, budget;
int preferences = 0;
String flooring = "";
Scanner s = new Scanner(System.in);
out.print("Enter the Room height : ");
rheight = s.nextDouble();
out.print("\nEnter the Room width : ");
rwidth = s.nextDouble();
out.print("\nEnter the Room length : ");
rlength = s.nextDouble();
//Taking number of Rooms as input
out.print("Enter the Number of Doors: ");
numberOfDoors=s.nextInt();
double totalDoorSize=0;
//calculate total size of doors by iterating over number of doors
for(int i=1;i<=numberOfDoors;i++){
out.print("\nEnter the Door"+i+" height : ");
dheight = s.nextDouble();
out.print("\nEnter the Door"+i+" width : ");
dwidth = s.nextDouble();
totalDoorSize=totalDoorSize+(dheight*dwidth);
}
//Taking number of Windows as input
out.print("Enter the Number of Windows: ");
numberOfWindows=s.nextInt();
double totalWindowSize=0;
//calculate total size of doors by iterating over number of windows
for(int i=1;i<=numberOfWindows;i++){
out.print("\nEnter the Window"+i+" height : ");
w1height = s.nextDouble();
out.print("\nEnter the Window"+i+" width : ");
w1width = s.nextDouble();
totalWindowSize=totalWindowSize+(w1height*w1width);
}
//Taking number of Bookcases as input
out.print("Enter the Number of Bookcases: ");
numberOfBookCases=s.nextInt();
double totalBookCasesCarpetArea=0,totalBookCasesPaintArea=0;
//calculate total size of doors by iterating over number of bookcase
for(int i=1;i<=numberOfBookCases;i++){
out.print("\nEnter the bookshelf"+i+" height : ");
bheight = s.nextDouble();
out.print("\nEnter the bookshelf"+i+" width : ");
bwidth = s.nextDouble();
out.print("\nEnter the bookshelf"+i+" length : ");
blength = s.nextDouble();
totalBookCasesCarpetArea=totalBookCasesCarpetArea+(bwidth*blength);
totalBookCasesPaintArea=totalBookCasesPaintArea+(bheight*blength);
}
//Commenting out hard coded values for number of doors,window and bookcases
/*out.print("\nEnter the Window1 height : ");
w1height = s.nextDouble();
out.print("\nEnter the Window1 width : ");
w1width = s.nextDouble();
out.print("\nEnter the Window2 height : ");
w2height = s.nextDouble();
out.print("\nEnter the Window2 width : ");
w2width = s.nextDouble();*/
/* out.print("\nEnter the bookshelf height : ");
bheight = s.nextDouble();
out.print("\nEnter the bookshelf width : ");
bwidth = s.nextDouble();
out.print("\nEnter the bookshelf length : ");
blength = s.nextDouble();*/
out.print("\nEnter the painting cost per square feet: $");
paintCost = s.nextDouble();
// out.print("\nEnter the carpenting cost per square feet: $");
// carpentCost = s.nextDouble();
out.print("\nChoose Flooring type : \n0: No Preferences\n1: Ceramic Tile \n2: Hardwood \n3: Carpet \n4: linoleum tile \n Enter Flooring type : ");
preferences = s.nextInt();
out.print("\nEnter your budget for flooring: ");
budget = s.nextDouble();
paintArea = 2 * rheight * (rwidth + rlength) - (totalBookCasesPaintArea) - (totalWindowSize) - (totalDoorSize); //calculation of paint area
carpentArea = (rwidth * rlength) - (totalBookCasesCarpetArea); //calculation of carpent area
/*paintArea = 2 * rheight * (rwidth + rlength) - (bheight * blength) - (w1width * w1height) - (w2width * w2height) - (dheight * dwidth); //calculation of paint area
carpentArea = (rwidth * rlength) - (bwidth * blength); //calculation of carpent area
*/ switch (preferences) {
case 0:
if (4 * carpentArea <= budget) {
carpentCost = 4;
flooring = "Ceramic Tile";
} else if (3 * carpentArea <= budget) {
carpentCost = 3;
flooring = "Hardwood";
} else if (2 * carpentArea <= budget) {
carpentCost = 2;
flooring = "Carpet";
} else if (1 * carpentArea <= budget) {
carpentCost = 1;
flooring = "Lenolieum Tile";
} else {
carpentCost = 0;
flooring = "";
}
break;
case 1:
if (4 * carpentArea <= budget) {
carpentCost = 4;
flooring = "Ceramic Tile";
} else {
carpentCost = 0;
}
break;
case 2:
if (3 * carpentArea <= budget) {
carpentCost = 3;
flooring = "Hardwood";
} else {
carpentCost = 0;
}
break;
case 3:
if (2 * carpentArea <= budget) {
carpentCost = 2;
flooring = "Carpet";
} else {
carpentCost = 0;
}
break;
case 4:
if (1 * carpentArea <= budget) {
carpentCost = 1;
flooring = "Lenolieum Tile";
} else {
carpentCost = 0;
}
break;
}
out.println("Area of wall after removing the paining area : " + paintArea);
out.println("Area of floor after removing area of bookshelf : " + carpentArea);
out.println("Cost for painting : $" + (paintArea * paintCost));
if (carpentCost != 0) {
out.println("flooring type : " + flooring);
out.println("Cost for flooring : $" + (carpentArea * carpentCost));
} else {
out.println("No Affordable flooring available in given budget");
}
}
}
/*
Renovation1
Enter the Room height : 12

Enter the Room width : 12

Enter the Room length : 12
Enter the Number of Doors: 3

Enter the Door1 height : 10

Enter the Door1 width : 2

Enter the Door2 height : 5

Enter the Door2 width : 3

Enter the Door3 height : 5

Enter the Door3 width : 3
Enter the Number of Windows: 0
Enter the Number of Bookcases: 1

Enter the bookshelf1 height : 10

Enter the bookshelf1 width : 2

Enter the bookshelf1 length : 8

Enter the painting cost per square feet: $1

Choose Flooring type :
0: No Preferences
1: Ceramic Tile
2: Hardwood
3: Carpet
4: linoleum tile
Enter Flooring type : 0

Enter your budget for flooring: 255.00
Area of wall after removing the paining area : 446.0
Area of floor after removing area of bookshelf : 128.0
Cost for painting : $446.0
flooring type : Lenolieum Tile
Cost for flooring : $128.0

Renovation 2
Enter the Room height : 8

Enter the Room width : 12

Enter the Room length : 24
Enter the Number of Doors:
0
Enter the Number of Windows: 3

Enter the Window1 height : 6

Enter the Window1 width : 2

Enter the Window2 height : 5

Enter the Window2 width : 3

Enter the Window3 height : 5

Enter the Window3 width : 8
Enter the Number of Bookcases: 2

Enter the bookshelf1 height : 6

Enter the bookshelf1 width : 3

Enter the bookshelf1 length : 8

Enter the bookshelf2 height : 6

Enter the bookshelf2 width : 2

Enter the bookshelf2 length : 3

Enter the painting cost per square feet: $1.57

Choose Flooring type :
0: No Preferences
1: Ceramic Tile
2: Hardwood
3: Carpet
4: linoleum tile
Enter Flooring type : 1

Enter your budget for flooring: 250.00
Area of wall after removing the paining area : 443.0
Area of floor after removing area of bookshelf : 258.0
Cost for painting : $695.51
No Affordable flooring available in given budget

Renovation 3
Enter the Room height : 12

Enter the Room width : 11.25

Enter the Room length : 12.75
Enter the Number of Doors: 1

Enter the Door1 height : 10

Enter the Door1 width : 1.95
Enter the Number of Windows: 2

Enter the Window1 height : 5

Enter the Window1 width : 2.5

Enter the Window2 height : 7.2

Enter the Window2 width : 6.8
Enter the Number of Bookcases: 1

Enter the bookshelf1 height : 6

Enter the bookshelf1 width : 3

Enter the bookshelf1 length : 8

Enter the painting cost per square feet: $0.95

Choose Flooring type :
0: No Preferences
1: Ceramic Tile
2: Hardwood
3: Carpet
4: linoleum tile
Enter Flooring type : 3

Enter your budget for flooring: 400.00
Area of wall after removing the paining area : 447.04
Area of floor after removing area of bookshelf : 119.4375
Cost for painting : $424.688
flooring type : Carpet
Cost for flooring : $238.875

*/

Please write the code with comments for everything thank you! and don't use objects

(Java) Building a Doubly Linked List off of an interface I am having trouble with these two methods

    @Override
    public void add(T newEntry) {
        DoubleLinkedNode newNode = new DoubleLinkedNode(newEntry);

        if (!isEmpty()) {

        }
        if (isEmpty()) {
            first = newNode;
            last = newNode;
        } else {
            last.setNextNode(newNode);
            newNode.setPreviousNode(last);
            last = newNode;
        }
//        length++;
        numElements++;

    }

    @Override
    public void add(int newPosition, T newEntry) {
        DoubleLinkedNode newAdder = new DoubleLinkedNode(newEntry);

        if ((newPosition >= 0) && (newPosition <= numElements)) {
            numElements++;
            if (newPosition == 0) {
                add(newEntry);
            } else if (newPosition >= getLength() + 1) {
                DoubleLinkedNode previousNode = getNodeAt(newPosition - 1);
                DoubleLinkedNode NextNode = previousNode.getNextNode();

                newAdder.setNextNode(NextNode);
                newAdder.setPreviousNode(previousNode);
                previousNode.setNextNode(newAdder);
                NextNode.setPreviousNode(newAdder);
            } else if (newPosition == getLength()) {

                DoubleLinkedNode previousNode = getNodeAt(newPosition - 1);

                previousNode.setNextNode(newAdder);
                newAdder.setPreviousNode(previousNode);

                last = newAdder;
            }
        } else {
            throw new IndexOutOfBoundsException("");
        }
    }
I cannot figure out how to get the add newEntry and other add method to work All the Method calls do what you'd think they'd do

Q. An Operating system is an intermediary agent between the user and the computer hardware. Explain !

(java)

Create a specification(your choice) of a data abstraction , decide a rep for the data abstraction. Write the abstraction function and the rep invariant for the rep.

Note* add comments for explanation..

A data structure can be defined as a mechanism for organizing the data a program stores in memory. An example of a data structure is a Linked List. Discuss how a linked list works and the methods of this data structure. (Please be super detailed and type the solution)

1 for each of the problems listed below write the c++ program while using WHILE loop structures

A program will display each term in the following sequence

1 -10 100 -1000 10000 -100000 1000000

A program will calculate and display the corresponding celsius temperatures for the given Farenheit ones from 0f to 212 f (hint c=(f-32/1.8)

2D object transformations(Use NetBeans IDE)
Task: create a program that realizes 2D transformations for 2D object with at least three
control points:
• Movement
o The user must be able to input the movement step (in pixels)
o The movement can be controlled with keyboard cursor keys (←↑→↓)
• Scaling
o The user must be able to input the scaling parameters
o The scaling should be controlled with keyboard keys (for example "Page
Up", "Page Down")
• Rotation
o The user must be able to input the angle of rotation (in degrees)
o The user must be able to input a point, around which the object will rotate
(X, Y)
o Automatic rotation must be implemented, the user pushes a button and the
object begins to rotate around the given point (animation using timer)

You are given a text file that contains the timetable for buses that travel a college campus. The first line of the file contains the name for each stop on the bus system separated by colons. Each following line contains the times using a 24-hour clock at which each bus in the system will arrive at a bus stop, also separated by colons.The timetable will have the following format:

Edinburgh:Danderhall:Dalkeith:Edgehead:Pathhead:Blackshiels:Oxton:Carfraemill:Lauder:Earlston:Leaderfoot:Newtown St Boswells:St Boswells:Clintmains:Kelso

0850:0911:0918:0930:0933:0939:0953:0955:1001:1015:1025:1029:1032:1038:1055

1150:1211:1218:1230:1233:1239:1253:1255:1301:1315:1325:1329:1332:1338:1355

1350:1411:1418:1430:1433:1439:1453:1455:1501:1515:1525:1529:1532:1538:1555

1610:1633:1640:1652:1655:1701:1715:1717:1723:1737:1746:1750:1753:1803:1820

1750:1811:1818:1830:1833:1839:1853:1855:1901:1919:1925:1929:1932:1938:1955

2000:2021:2028:2037:2040:2046:2100:2102:2108:2121:2126:2130:2133:2138:2155

Write a program in Python that reads this file and outputs a row for each bus stop, showing the times when a bus arrives at that stop

Convert signed integer 0xACE9 to binary and decimal.

Convert unsigned integer0xACE9 to binary and decimal.

The Harrison Group Life Insurance company computes annual policy premiums based on the age the customer turns in the current calendar year. The premium is computed by taking the decade of the customer’s age, adding 15 to it, and multiplying by 20.

For example, a 34-year-old would pay $360, which is calculated by adding the decades (3) to 15 and then multiplying by 20.

Write an application that prompts a user for the current year then a birth year. Pass both to a method that calculates and returns the premium amount, and then display the returned amount.

Insurance.java

Outline the process that occurs when a hardware interrupt is generated by a disk controller. Set the context for the interrupt disk read and describe how an interrupt handler would address the event.

finish the java programming

Create a new class named MyCharacterListTools that provides the API shown below.

This class does not need a constructor nor will any user-defined constructor be called by the

provided code in MainClassQ1.java.

◦ MyLinkedList createCharacterList(String str) – This method is to

return a MyLinkedList whose data items are the characters of str. All of the

characters must appear in the list and in the same order as they are given in str.

◦ void removeNonLetters(MyLinkedList list) – This method is to remove

from the list any spaces, numbers and punctuation characters (this is to be done inplace).

Letters of the alphabet are to be left in the list in the same order they were given.

For example, if the list contained {H_e_l_l_o_ _W_o_r_l_d_!} then after calling this

function, the list would hold {H_e_l_l_o_W_o_r_l_d}. You may use the built-in Java

static method Character.isLetter(char ch) to test whether the list items are

letters.

◦ boolean testEquality(MyLinkedList l1, MyLinkedList l2) – This

method is to compare two MyLinkedLists for equality. Two lists are considered

equal if their contents are the same and in the same order. Letter case should not be

observed (i.e. 'A' is equal to 'a', 'B' is equal to 'b', etc...). If the two lists are equal then

return true. Return false otherwise. The static built-in Java methods

Character.toLowerCase(char ch) and Character.toUpperCase(char

ch) may be used in this method.