Question

Write a python function called HackCaesar with the following requirements:

def hack_caesar(cyphertext): ‘’’ cyphertext is a text encoded using Caesars encryption. The encryption key is unknown. The function returns the correct encryption key. Hint: Use the function we wrote was called caesar(c, key) and could encode a single character.

# YOUR CODE GOES HERE

def is_odd(n):

return n%2 == 1

def caesar(c, key):

""" Encrypts a lower case character c using key

Example: if c = "a" and key=3 then the function should return d

"""

return chr((ord(c)-97+key) % 26 + 97)

n = input("enter a number:")

n = int(n)

if n > 10:

print("hello")

print("your number if more than 10")

else:

print("else block")

for i in range(5):

print(i)

print(i*i)

print(is_odd(i))

print(caesar("a", 3))

Answer 1

#source code:

def caesar(c,key):
   c=c.upper()
   list=[x for x in range(0,26)]
   letter=[chr(x) for x in range(65,91)]
   cypher=""
   for i in range(len(c)):
       for j in range(len(letter)):
           if(c[i]==letter[j]):
               form=(j+key)%26
               cypher+=letter[form]
   return cypher
def hack_caesar(cyphertext):
   for key in range(1,27):
       letter=[chr(x) for x in range(65,91)]
       plain=""
       for i in range(len(cyphertext)):
           for j in range(len(letter)):
               if(cyphertext[i]==letter[j]):
                   form=(j-key)%26
                   plain+=letter[form]
       print("plain_String:{} And Key={}".format(plain,key))

if __name__=="__main__":
   #for excryption
   text=input("Enter text to Encrypt:")
   key=int(input("Enter key to Encrypt:"))
   cypher=caesar(text,key)
   print(cypher)
  
   #for decryption
   hack_caesar(cypher)
  

#output:

#based on output we simply said key 3 is meaning full data so key is 3

#if you have any doubt comment below.