Question

In: Physics

In reaching her destination, a backpacker walks with an average velocity of 1.05 m/s, due west....

In reaching her destination, a backpacker walks with an average velocity of 1.05 m/s, due west. This average velocity results, because she hikes for 5.66 km with an average velocity of 2.54 m/s due west, turns around, and hikes with an average velocity of 0.403 m/s due east. How far east did she walk (in kilometers)?

Solutions

Expert Solution

An average velocity which will be given by -

avg = s / t

We know that, avg = (dwest - deast) / (twest + teast)

where, twest = (dwest / vwest) and teast = (deast / veast)

then, we get

avg = (dwest - deast) / [(dwest / vwest) + (deast / veast)]

[(dwest / vwest) + (deast / veast)] = (dwest - deast) / avg

[(dwest / vwest) + (deast / veast)] = (dwest / avg) - (deast / avg)

(deast / veast) + (deast / avg) = (dwest / avg) - (dwest / vwest)

deast [(1 / veast) + (1 / avg)] = dwest [(1 / avg) - (1 / vwest)]

deast [(avg + veast) / avg veast] = dwest [(vwest - avg) / avg vwest]

deast = dwest [(vwest - avg) / avg vwest] [avg veast / (avg + veast)]

deast = dwest (veast / vwest) [(vwest - avg) / (veast + avg)]

deast = (5.66 km) [(0.403 m/s) / (2.54 m/s)] {[(2.54 m/s) - (1.05 m/s)] / [(0.403 m/s) + (1.05 m/s)]}

deast = (5.66 km) (0.1586) (1.0254)

deast = 0.92 km


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