In: Physics
In reaching her destination, a backpacker walks with an average velocity of 1.05 m/s, due west. This average velocity results, because she hikes for 5.66 km with an average velocity of 2.54 m/s due west, turns around, and hikes with an average velocity of 0.403 m/s due east. How far east did she walk (in kilometers)?
An average velocity which will be given by -
avg
=
s /
t
We know that,
avg
= (dwest - deast) / (twest +
teast)
where, twest = (dwest / vwest) and teast = (deast / veast)
then, we get
avg
= (dwest - deast) / [(dwest /
vwest) + (deast / veast)]
[(dwest / vwest) + (deast /
veast)] = (dwest - deast) /
avg
[(dwest / vwest) + (deast /
veast)] = (dwest /
avg)
- (deast /
avg)
(deast / veast) + (deast /
avg)
= (dwest /
avg)
- (dwest / vwest)
deast [(1 / veast) + (1 /
avg)]
= dwest [(1 /
avg)
- (1 / vwest)]
deast [(
avg
+ veast) /
avg
veast] = dwest [(vwest -
avg)
/
avg
vwest]
deast = dwest [(vwest -
avg)
/
avg
vwest] [
avg
veast / (
avg
+ veast)]
deast = dwest (veast /
vwest) [(vwest -
avg)
/ (veast +
avg)]
deast = (5.66 km) [(0.403 m/s) / (2.54 m/s)] {[(2.54 m/s) - (1.05 m/s)] / [(0.403 m/s) + (1.05 m/s)]}
deast = (5.66 km) (0.1586) (1.0254)
deast = 0.92 km