Question

In: Math

a) do the laplace transform to; x(t)= e^2t . sin(3t) . sin (t) b) do the...

a) do the laplace transform to;

x(t)= e^2t . sin(3t) . sin (t)

b) do the inverse laplace transform to;

x(s) = (3s-5) / ( (s+1).(s^2+2s+5) )

Solutions

Expert Solution

feel free to ask if you have any doubt and if you liked my answer please give a thumbs up.


Related Solutions

Consider the helix r(t)=(cos(2t),sin(2t),−3t)r(t)=(cos(2t),sin(2t),−3t). Compute, at t=π/6 A. The unit tangent vector T=T= ( , ,...
Consider the helix r(t)=(cos(2t),sin(2t),−3t)r(t)=(cos(2t),sin(2t),−3t). Compute, at t=π/6 A. The unit tangent vector T=T= ( , , ) B. The unit normal vector N=N= ( , , ) C. The unit binormal vector B=B= ( , , ) D. The curvature κ=κ=
Solve the partial differential equation by Laplace transformu_x (x,t)+u_t (x,t)=e^3t given that u(x,o)=0 , u(o,t)=e^3t
Solve the partial differential equation by Laplace transformu_x (x,t)+u_t (x,t)=e^3t given that u(x,o)=0 , u(o,t)=e^3t
3sin(t)+3sin(t)sin(2t)=3cos(t)-cos(3t). I'm trying to solve for t.
3sin(t)+3sin(t)sin(2t)=3cos(t)-cos(3t). I'm trying to solve for t.
Solve this Initial Value Problem using the Laplace transform: x''(t) - x'(t) - 6x(t) = e^(4t),...
Solve this Initial Value Problem using the Laplace transform: x''(t) - x'(t) - 6x(t) = e^(4t), x(0) = 1, x'(0) = 1
Laplace Transform : y ' - y = e^-3t cos3t , y(0) =3 and, Show that,...
Laplace Transform : y ' - y = e^-3t cos3t , y(0) =3 and, Show that, Differential Form ? dU = Tds - Pdv , dH=Tds-Vdp , dF= -sdT-Pdv , dG= -sdT+VdP
Convert x=cos(3t)+sin(3t) & y=cos(t)-sin(t) into an equation of x-y form (cartesian equation). Thank you
Convert x=cos(3t)+sin(3t) & y=cos(t)-sin(t) into an equation of x-y form (cartesian equation). Thank you
For this parametrized curve: x = e^(2t) sin t , y = cos(4t) find tangent line...
For this parametrized curve: x = e^(2t) sin t , y = cos(4t) find tangent line to curve when t=1
Solve using Laplace Transform: 1) y'' - 2y' + 5y = cos(2t) - cos(2t)u4pi(t); y(0) =...
Solve using Laplace Transform: 1) y'' - 2y' + 5y = cos(2t) - cos(2t)u4pi(t); y(0) = 0, y'(0) = 0
Consider the spiral path x(t) = (cos^2t,sin^2t,t) for 0 ≤ t ≤ π/2. Evaluate the integral...
Consider the spiral path x(t) = (cos^2t,sin^2t,t) for 0 ≤ t ≤ π/2. Evaluate the integral x dx−y dy + z^2 dz
Solve by variation of parameters: A. y"−9y = 1/(1 − e^(3t)) B. y" +2y'+26y = e^-t/sin(5t)
Solve by variation of parameters: A. y"−9y = 1/(1 − e^(3t)) B. y" +2y'+26y = e^-t/sin(5t)
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT