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The ΔHvap of a certain compound is 22.01 kJ·mol–1 and its ΔSvap is 54.70 J·mol–1·K–1. What...

The ΔHvap of a certain compound is 22.01 kJ·mol–1 and its ΔSvap is 54.70 J·mol–1·K–1. What is the boiling point of this compound?

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Expert Solution

Answer – We are given, amide and water and this is the hydrolysis of amide gives carboxylic acid and amine as the product as follow –

The ΔHvap of a certain compound is 22.01 kJ·mol–1 and its ΔSvap is 54.70 J·mol–1·K–1. What is the boiling point of this compound?

Answer – We are given, ΔHvap = 22.01 kJ·mol-1 , ΔSvap = 54.70 J·mol-1.K-1

We need to convert the ΔSvap J to kJ

We know,

1000 J = 1 kJ

So, 54.70 J = ?

= 0.05470 kJ

We know formula

T = ΔHvap / ΔSvap

   = 22.01 kJ·mol-1 / 0.05470 J·mol-1.K-1

= 402.4 K

So, boiling point of this compound = 402.4- 273.15

                                                         = 129.2 oC.

so boiling point of this compound is 402 K or 129.2oC

queen_honey_blossom answered 1 hour ago
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