Question

draw the Lewis dot diagram of the following molecules:
a. BBr3
b. IF2-
c. SiO2
d. SOF2

Answer 1

First count the total number of valence electrons in as follows:

Next draw the skeletal structure of shown as follows:

There are six valence electrons in the above structure, so the remaining valence electrons are 18. So, complete octet for bromine atom by placing 18 valence electrons as lone pairs on bromine.

Therefore, the final Lewis structure of is as follows:

First count the total number of valence electrons in as follows:

Next draw the skeletal structure of shown as follows:

There are four valence electrons in the above structure, so the remaining valence electrons are 18. So, complete octet for fluorine atom by placing 12 valence electrons as lone pairs on fluorine remaining electrons on central atom iodide atom.

Therefore, the final Lewis structure of is as follows:

First count the total number of valence electrons in as follows:

Next draw the skeletal structure of shown as follows:

There are four valence electrons in the above structure, so the remaining valence electrons are 12. So, complete octet for oxygen atom by placing 12 valence electrons as lone pairs on oxygen.

Therefore, the final Lewis structure of is as follows: