A 0.30-kg ball is thrown with a speed of 7.0m/s at an upward angle of 23?....

A 0.30-kg ball is thrown with a speed of 7.0m/s at an upward angle of 23?. Use conservation of energy

Part A

What is its speed at its highest point?

Part B

How high does it go?

Expert Solution

Suppose the ball with mass m = 0.3 kg is thrown with speed v=7 m/s at an upward angle of .

PART A Now we decompose the velocity to x and y components then,

The horizontal component of the velocity v_x of the object remains unchanged throughout the motion as no force along x direction. But the vertical component of velocity v_y decreases gradually due to the acceleration of gravity acting downwards. At the highest point vertical component of the velocity will bw zero. Therefore at highest point the speed of the ball is,

PART B Only the y component of velocity v_y will determine the motion in y direction. Suppose H_max is the highest point of the ball, then the potential energy at this point must be equal to the kinetic energy due to initial v_y for conservation of energy . Then we get,

genius_generous answered 1 hour ago

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