In: Chemistry
Which transition metal is correctly matched with its highest oxidation state??
A) Cr, 3+?
B) Mn, 5+?
C) Ti, 3+
?D) Sc, 3+
?E) Fe, 8+
(A) The electronic configuration of Cr(At No:24) is : [Ar]4s1 3d5
So there is 1 electron in s orbital & 5 electrons in d orbital,so we can remove a maximum of 6 elctrons totally.
therefore the maximum oxidation state is +6
(B) The electronic configuration of Mn(At No:25) is : [Ar]4s2 3d5
So there is 2 electrons in s orbital & 5 electrons in d orbital,so we can remove a maximum of 7 elctrons totally.
therefore the maximum oxidation state is +7
(C) The electronic configuration of Ti(At No:22) is : [Ar]4s2 3d2
So there is 2 electrons in s orbital & 2 electrons in d orbital,so we can remove a maximum of 4 elctrons totally.
therefore the maximum oxidation state is +4
(D) The electronic configuration of Sc(At No:21) is : [Ar]4s2 3d1
So there is 2 electrons in s orbital & 1 electron in d orbital,so we can remove a maximum of 3 elctrons totally.
therefore the maximum oxidation state is +3
(E) The electronic configuration of Fe(At No:26) is : [Ar]4s2 3d6
So there is 2 electrons in s orbital & 4 unpaired electrons in d orbital,so we can remove a maximum of 6 elctrons totally.
therefore the maximum oxidation state is +8
Therfore the correct answer is (D)