Consider the reaction, 2 D(g) + 3 E(g) + F(g) => 2 G(g) + H(g) When...

Consider the reaction, 2 D(g) + 3 E(g) + F(g) => 2 G(g) + H(g) When H is increasing at 0.85 mol/Ls, how quickly is F decreasing?

Solutions

Expert Solution

The reaction is as follows:

2D(g) + 3E(g) + F(g) 2G(g) + H(g)

The rate expression for the reaction is as follows:

Rate = -1/2{[D]/t} = -1/3{[E]/t} = -[F]/t = 1/2{[G]/t} = [H]/t

The rate of change of H {[H]/t}= 0.85 mol/L

The relation between [F]/t and [H]/t is as follows:

As per the rate expression,

-[F]/t = [H]/t

[F]/t = -[H]/t

[F]/t = - 0.85 mol/L.s

Negative sign indicates that F is decreasing.

Hence, F is decreasing with a rate of 0.85 mol/L.s.

queen_honey_blossom answered 1 year ago

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