In: Physics

# An electric flux of 157 N.m2/C passes through a flat horizontal surface that has an area...

An electric flux of 157 N.m2/C passes through a flat horizontal surface that has an area of 0.87 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15o above the horizontal?

## Solutions

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An electric flux of 157 N.m2/C passes through a flat horizontal surface that has an area of 0.72 m2. The flux is due to a uniform electric field. What is the magnitude of the electric field if the field points 15o above the horizontal?

2-a-

Given

the electric flux     f = 157 N m2/C

Area of the surface A = 0.72 m^2

The electric flux     f = E.A..............(1)

Here E is electric field

A is area of the plate through which the electric flux passes

rewrite the equation (1)

the electicfield    E = f/A = (157 N.m^2/C)/0.72 m^2

E =151.65 N/C

if the electric field made 15^0 with the surface

then electric flux f = EAcos?

f = (151.65 N/C)(0.72)cos15^0

f = 190.18 N m^2/C

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