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In: Physics

A positron with kinetic energy 2.5 keV is projected into a uniform magnetic field Bvec of...

A positron with kinetic energy 2.5 keV is projected into a uniform magnetic field Bvec of magnitude 0.90 T, with its velocity vector making an angle of 89° with Bvec. Find the following values for the positron's helical path.

(a) the period

____s

(b) the pitch

____m

(c) the radius

_____m

Expert Solution

mass of the positron is m=9.1 x 10^-31 kg

charge is q=1.6 x 10^-19C

strength of the magnetic field is B=0.9T

kinetic energy is K=2.50keV=2.5 x 10³ x 1.6 x 10^-19J

0.5mv²=4 x 10^-16 J

0.5 x 9.1 x 10^-31 x v² =4x 10^-16

v=2.96 x 10⁷m/s

a)the period is T=2?m/qB

=2?(9.1 x 10^-31 )/1.6 x 10^-19x 0.90

=39.68ns

b)pitch is p=vcos?(2?m/qB)

=2.96 x 10⁷x cos89(39.68 x 10^-9)

=20.49 x 10^-3

c) radius is r=mvsin?/qB

=(9.1 x 10^-31 )2.96 x 10⁷x sin89/1.6 x 10^-19x 0.9

=18.7 x 10^-5 m

genius_generous answered 2 hours ago

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