Situation 21.1 Two identical small conducting spheres are separated by 0.60m. The spheres carry different amounts...

Situation 21.1

Two identical small conducting spheres are separated by 0.60m. The spheres carry different amounts of charge and each sphere experiences an attractive electric force of 10.8N. The total charge on the two spheres is -24 ?C.

In Situation 21.1, the two spheres are connected by a slender conducting wire, which is then removed. The electric force on each sphere is closest to:

Situation 21.1

Two identical small conducting spheres are separated by 0.60m. The spheres carry different amounts of charge and each sphere experiences an attractive electric force of 10.8N. The total charge on the two spheres is -24 C.

In Situation 21.1, the two spheres are connected by a slender conducting wire, which is then removed. The electric force on each sphere is closest to:

	zero
	5.4 N, attractive
	5.4 N, repulsive
	3.6 N, attractive
	3.6 N, repulsive

Solutions

Expert Solution

after connecting the two spheres will have the average charge=(q₁+q₂)/2

=-24?c/2

=-12?c

the force between themisF=(1/4??)q₁q₂/r²

=9*10^9*144*10^-12C/0.36m^2

=3.6N repulsive

option (c) is correct answer.

genius_generous answered 1 year ago

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