Question

A proton and an electron are moving due east in a constant electric field that also points due east. The electric field has a magnitude of 3.0

Answer 1

since

          F = |q|*E   and also   F = m*a   then

           a = (|q|*E)/m

for proton :

               m = 1.672*10^{-27} kg and q = 1.6*10^{-19} C then

             Acceleration,a is

                                

for electron :

               m = 9.1*10^{-31} kg and q = 1.6*10^{-19} C then

             Acceleration,a is